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To find \( y_1 \), which represents the mole fraction of acetone in the gas entering the condenser, we need to apply the principle of mass balance, using the data provided in the problem.

Given:
- After the condenser, the gas stream has a mole fraction of acetone, \( y_3 = 0.0680 \).
- The liquid stream from the condenser is \( n_l = 43.0 \) lb-mol acetone/min.
- The air/acetone ratio leaving the condenser is \( y_3 = 0.0680 \) lb-mol acetone/lb-mol and \( s_3 = 0.9320 \) lb-mol air/lb-mol.

Assuming we have the following information:
1. The inlet air is dry.
2. We know the condensation temperature \( T_2 \) is 20°F.

Now, to determine \( y_1 \), you can use a mass balance equation around the condenser. We can set up a molar balance based on the acetone input and output. This balance should consider both the air and acetone flows.

Please confirm if you have additional details on the total incoming vapor stream (in lb-mol/min) or if there are any more details on the air stream. This will help in calculating \( y_1 \) precisely.

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Would you like to see detailed steps, or do you have more information? Here are some related questions for deeper understanding:

1. How do we perform a mass balance around a condenser?
2. What role does temperature play in determining condensation levels?
3. Why is the mole fraction of acetone in the vapor stream important?
4. How does air flow affect the condensation process?
5. What calculations would change if the relative humidity differed?

**Tip:** When dealing with mole fractions in multi-component systems, always account for total moles in each stream for accurate balancing.

Learn how to determine the mole fraction of acetone (y1) entering a condenser when the exit temperature T2 is 20°F. This problem involves concepts such as mass balance, mole fraction, and condensation in chemical engineering processes. Suitable for undergraduate chemical engineering students.

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