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Let's solve the problem step by step.

### Part a: Factors of 63

We need to check which numbers among 2, 3, 5, and 10 are factors of 63.

- **63 ÷ 2 = 31.5**: Since 31.5 is not an integer, **2 is not a factor**.
- **63 ÷ 3 = 21**: Since 21 is an integer, **3 is a factor**.
- **63 ÷ 5 = 12.6**: Since 12.6 is not an integer, **5 is not a factor**.
- **63 ÷ 10 = 6.3**: Since 6.3 is not an integer, **10 is not a factor**.

Thus, the only factor of 63 from the list is **3**.

### Part b: Explaining why others are not factors

- **2 is not a factor** because 63 is an odd number, and odd numbers cannot be divided evenly by 2.
- **5 is not a factor** because 63 does not end in 0 or 5, and a number must end in 0 or 5 to be divisible by 5.
- **10 is not a factor** because 63 does not end in 0, and a number must end in 0 to be divisible by 10.

Would you like further clarification or details on this problem?

Here are five related questions:
1. What is the prime factorization of 63?
2. How do you find the greatest common factor (GCF) of 63 and another number?
3. What are the multiples of 63 within 200?
4. How would you find all factors of a number, like 63?
5. Can you explain the difference between a factor and a multiple?

**Tip:** To quickly check if a number is divisible by 3, sum its digits. If the sum is divisible by 3, the number itself is divisible by 3. (For example, 6 + 3 = 9, which is divisible by 3, so 63 is divisible by 3.)

Which of the following numbers is a factor of 63? (2, 3, 5, 10). For each number that is not a factor of 63, explain how you know this.

Learn how to check whether 2, 3, 5, and 10 are factors of 63. Understand the rules of divisibility and why certain numbers do not divide evenly into 63. Suitable for students in Grades 5-7.

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