Math Problem Statement
solve using augmented matrix
Solution
The problem asks to find the dimension of the subspace spanned by the set of vectors given as:
To determine the dimension of , we will solve the problem by forming an augmented matrix with these vectors as columns, and then row-reducing the matrix to determine its rank, which will give us the dimension of the subspace . The vectors form the following matrix:
0 & -1 & 2 & 0 \\ 1 & -1 & 3 & 1 \\ 1 & -2 & 5 & 1 \\ -1 & 2 & -5 & -2 \end{bmatrix}$$ Let's row-reduce this matrix to find the rank. I will now proceed with the row-reduction process.The rank of the matrix is 3, which means that the dimension of the subspace $$H$$ is 3. Now, to determine a basis for $$H$$, we need to find 3 linearly independent vectors from the original set of vectors. Since the rank is 3, these vectors span the subspace. One way to find the basis is to examine the row-reduced form of the matrix, but since the rank is 3, any 3 linearly independent columns will form a basis. Would you like a step-by-step guide to determining the basis, or do you have any other questions? Here are 5 related questions for further exploration: 1. How can we verify if a set of vectors is linearly independent? 2. What is the geometric interpretation of the dimension of a subspace? 3. How would the process change if the vectors spanned a higher-dimensional space? 4. How can we confirm if a vector belongs to a given subspace? 5. What is the relationship between the rank of a matrix and the number of pivot columns? **Tip:** The dimension of a subspace is equivalent to the number of linearly independent vectors that span it, which can be determined by the rank of the matrix formed by the vectors.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Vector Spaces
Subspaces
Span
Basis
Dimension
Formulas
Rank(A) = Dimension of Span
Row-reduction (Gaussian Elimination)
Theorems
Rank-Nullity Theorem
Definition of Subspace Basis
Suitable Grade Level
University Level (Linear Algebra)
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