Math Problem Statement

Given the circuit below determine: 1. The capacitor C1 reactance Xc. 2. The phase shift θ. 3. Total impedance Z.

Solution

To solve the given questions for the RC circuit, let's go through each part:

Given Data

  • Resistor R1=40ΩR_1 = 40 \, \Omega
  • Capacitor C1=50μF=50×106FC_1 = 50 \, \mu \text{F} = 50 \times 10^{-6} \, \text{F}
  • Voltage V=12VV = 12 \, \text{V} at frequency f=60Hzf = 60 \, \text{Hz}

Solution Steps

a) The Capacitor C1C_1 Reactance (XCX_C)

The capacitive reactance XCX_C is given by: XC=12πfCX_C = \frac{1}{2 \pi f C} Substitute the values: XC=12π×60×50×106X_C = \frac{1}{2 \pi \times 60 \times 50 \times 10^{-6}} Calculating this will give us XCX_C.

b) The Phase Shift θ\theta

The phase shift θ\theta between the voltage and current in an RC circuit is given by: θ=arctan(XCR)\theta = \arctan\left(-\frac{X_C}{R}\right) Once we have XCX_C from part (a), we can substitute R=40ΩR = 40 \, \Omega and calculate θ\theta.

c) Total Impedance ZZ

The total impedance ZZ in an RC series circuit is: Z=R2+XC2Z = \sqrt{R^2 + X_C^2} Again, substituting R=40ΩR = 40 \, \Omega and XCX_C from part (a) will allow us to find ZZ.

Let’s compute these values now.import math

Given values

R = 40 # resistance in ohms C = 50e-6 # capacitance in farads (50 µF) f = 60 # frequency in Hz

Part a: Capacitive Reactance (X_C)

X_C = 1 / (2 * math.pi * f * C)

Part b: Phase Shift (θ)

theta = math.atan(-X_C / R) # in radians

Part c: Total Impedance (Z)

Z = math.sqrt(R2 + X_C2)

Convert theta from radians to degrees for interpretation

theta_degrees = math.degrees(theta)

X_C, theta_degrees, Z(53.05164769729845, -52.984355426817935, 66.4415331204682)(53.05164769729845, -52.984355426817935, 66.4415331204682)successHere are the results for each part:

  1. Capacitor C1C_1 Reactance (XCX_C): XC53.05ΩX_C \approx 53.05 \, \Omega
  2. Phase Shift θ\theta: θ52.98\theta \approx -52.98^\circ
  3. Total Impedance ZZ: Z66.44ΩZ \approx 66.44 \, \Omega

Would you like further details on any of these calculations, or do you have additional questions?

Related Questions

  1. How does the frequency affect the capacitive reactance in an RC circuit?
  2. What would be the effect on impedance if we increased the capacitance value?
  3. How can the phase shift θ\theta be interpreted in terms of voltage and current lead or lag?
  4. What would be the new impedance if we replaced the capacitor with a different value?
  5. How does phase shift θ\theta change with varying resistance in the circuit?

Tip

In RC circuits, the capacitor’s reactance XCX_C decreases with increasing frequency, causing changes in impedance and phase shift.

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Math Problem Analysis

Mathematical Concepts

AC Circuits
Reactance
Phase Shift
Impedance

Formulas

Capacitive reactance Xc = 1 / (2πfC)
Phase shift θ = arctan(-Xc / R)
Total impedance Z = sqrt(R^2 + Xc^2)

Theorems

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Suitable Grade Level

College/University Level