Math Problem Statement
Solution
The image shows three problems involving derivatives and logarithms. Let's solve them one by one.
Problem 1:
Given:
To differentiate with respect to , we will use the chain rule. Recall the derivative of a logarithmic function: where and .
First, let's find :
Now, using the formula for the derivative of a logarithm:
Thus, the derivative is:
Problem 2:
Given:
We apply the chain rule again. The derivative of is , and we have .
First, differentiate the outer function:
Now, multiply by the derivative of the inner function :
Thus, the derivative is:
Problem 3:
Given:
This is a composite function, so we apply the chain rule. First, we differentiate the outer function with respect to , then differentiate the inner function.
First, the outer function:
Now, apply the chain rule:
We now differentiate the logarithm : where and .
First, compute :
Thus:
Now substitute back into the expression for :
Do you need further clarification on any of these solutions? Let me know if you'd like a detailed breakdown of any steps!
Here are five related questions you might want to explore:
- How do you differentiate when is more complex?
- Can you apply the product rule and chain rule together in logarithmic functions?
- How would you handle logarithmic derivatives when the base is a variable rather than a constant?
- What are the applications of logarithmic differentiation in real-world problems?
- How would the rules change if natural logarithms were involved?
Tip: Remember that logarithmic differentiation is especially useful when dealing with products or quotients of functions, particularly when those functions are raised to powers.
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Math Problem Analysis
Mathematical Concepts
Logarithmic Differentiation
Chain Rule
Logarithmic Functions
Derivatives
Formulas
Derivative of log base a: d/dx[log_a(u)] = 1 / (u ln(a)) * du/dx
Derivative of natural logarithm: d/dx[ln(u)] = 1 / u * du/dx
Chain Rule: d/dx[f(g(x))] = f'(g(x)) * g'(x)
Theorems
Chain Rule
Logarithmic Differentiation Theorem
Suitable Grade Level
College-Level Calculus or Advanced High School
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