The given equation is $y = 4(0.95)^x$, which represents an exponential decay function. The general form of an exponential decay function is:

$y = a(1 - r)^x$

Where:

• $a$ is the initial value (in this case, $4$),
• $r$ is the decay rate,
• $(1 - r)$ is the decay factor (here, $0.95$),
• $x$ is the independent variable.

From the equation, we can identify the decay factor as $0.95$, which means $1 - r = 0.95$. Solving for $r$:

$1 - r = 0.95$ $r = 1 - 0.95 = 0.05$

Thus, the decay rate is 5%.

Would you like further details or have any questions?

Here are 5 related questions:

1. What is the initial value of the function?
2. How would the graph of the function change if the decay rate increased?
3. What is the half-life of the function?
4. How does the decay factor relate to the decay rate?
5. How does the function behave as $x$ approaches infinity?

Tip: The decay rate represents the percentage decrease per unit of time or input (in this case, per $x$).