Math Problem Statement

The daily cost of hiring a lawn service, y, to work x hours mowing the grounds on a golf course can be modeled using a linear function. The lawn service charges a fixed cost of $100, plus an additional cost of $25 per hour. The lawn service works a maximum of 6 hours per day. For one day of work, what is the range of the function for this situation?

Solution

Let's break down the problem in the image:

We are asked to find the range of the function yy, which represents the daily cost of hiring a lawn service for xx hours. The function given is linear, and the problem gives us:

  • A fixed cost of $100
  • An additional cost of $25 per hour
  • The maximum number of hours the lawn service can work is 6 hours per day.

The cost function y(x)y(x) can be written as: y=100+25xy = 100 + 25x Where xx is the number of hours worked, and the lawn service works for a maximum of 6 hours, so 0x60 \leq x \leq 6.

Finding the range of yy:

  1. When x=0x = 0 hours (minimum), the cost is: y=100+25(0)=100y = 100 + 25(0) = 100
  2. When x=6x = 6 hours (maximum), the cost is: y=100+25(6)=100+150=250y = 100 + 25(6) = 100 + 150 = 250

Thus, the range of the function is 100y250100 \leq y \leq 250.

Correct Answer:

The correct answer is b. 100y250100 \leq y \leq 250.

Would you like further details or have any other questions?


Here are 5 related questions you might consider:

  1. How do you find the range of a function from its equation?
  2. How would the range change if the fixed cost increased?
  3. What if the cost per hour was $30 instead of $25? How would that affect the range?
  4. How do you interpret the domain and range in a real-life situation like this?
  5. What are the differences between linear and non-linear cost functions?

Tip: Always look at the domain first when asked to find the range of a function, especially in practical scenarios.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Cost Modeling

Formulas

y = 100 + 25x

Theorems

Range of a linear function

Suitable Grade Level

Grades 8-10