https://file.aiquickdraw.com/mathbot/file/1729757306529pq70pwwv.jpg

Let's break down the problem and solve it step by step.

### Given:
- The cost of 3 magnets is **€6.15**, so the cost of each magnet is:
  \[
  \frac{6.15}{3} = 2.05 \text{ euros per magnet}.
  \]

- Alan has **£43** and the exchange rate is **£1 = €1.19**.

### Step 1: Convert pounds to euros.
To find out how many euros Alan has after converting £43:
\[
43 \times 1.19 = 51.17 \text{ euros}.
\]

### Step 2: Calculate how many magnets he can buy.
Since each magnet costs **€2.05**, the number of magnets Alan can buy is:
\[
\frac{51.17}{2.05} \approx 24.96.
\]
Since Alan can't buy a fraction of a magnet, he can buy **24 magnets**.

### Answer: 
Alan can buy **24 souvenir magnets**.

Would you like any more details or have any further questions on this problem? Here are some related questions you can explore:

1. How would the number of magnets change if the exchange rate improved to £1 = €1.25?
2. What if the price of the magnets increased to €2.50 each?
3. How many magnets could Alan buy if he only had £30?
4. What would happen if there was a transaction fee during the currency conversion?
5. How much money would Alan have left after buying the magnets?

**Tip:** When converting currencies, always make sure to perform the conversion before using the money for any purchases, as exchange rates can significantly affect buying power.

Alan is buying some souvenir magnets. 3 magnets cost €6.15. Each magnet costs the same amount. Alan converts £43 to euros (€) using an exchange rate of £1 = €1.19. How many of these souvenir magnets can he buy with the money he receives?

Learn how to calculate how many souvenir magnets can be purchased with £43 when converted to euros at an exchange rate of £1 = €1.19. The total cost for 3 magnets is €6.15. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation