Math Problem Statement

The following table shows crashworthiness ratings for 16 cars. (3 = Good, 2 = Acceptable, 1 = Marginal, 0 = Poor)

Frontal Crash Test Rating

3

2

1

0

Frequency

1

10

3

2

(a) Find the relative frequency distribution for the experiment of choosing a car at random and determining its frontal crash rating. (Enter your answers to four decimal places.)

Good (3)

Acceptable (2)

Marginal (1)

Poor (0)

(b) What is the relative frequency that a randomly selected car will have a crash test rating of "Marginal" or worse? (Enter your answer to four decimal places.)

Solution

To solve this problem, we need to calculate the relative frequencies of each crashworthiness rating category. The relative frequency is the proportion of cars in each category, which is found by dividing the frequency of each category by the total number of cars.

Part (a): Relative Frequency Distribution

Step 1: Calculate the Total Number of Cars

The total number of cars can be calculated by adding the frequencies of all categories: Total cars=1+10+3+2=16\text{Total cars} = 1 + 10 + 3 + 2 = 16

Step 2: Calculate Relative Frequency for Each Rating

The formula for relative frequency is: Relative Frequency=Frequency of each categoryTotal number of cars\text{Relative Frequency} = \frac{\text{Frequency of each category}}{\text{Total number of cars}}

  • Good (3): Relative Frequency=116=0.0625\text{Relative Frequency} = \frac{1}{16} = 0.0625

  • Acceptable (2): Relative Frequency=1016=0.6250\text{Relative Frequency} = \frac{10}{16} = 0.6250

  • Marginal (1): Relative Frequency=316=0.1875\text{Relative Frequency} = \frac{3}{16} = 0.1875

  • Poor (0): Relative Frequency=216=0.1250\text{Relative Frequency} = \frac{2}{16} = 0.1250

Part (b): Relative Frequency of "Marginal or Worse"

The crash test rating of "Marginal or worse" includes both Marginal (1) and Poor (0) ratings. We need to sum the relative frequencies of these two categories:

Relative Frequency of Marginal or Worse=0.1875+0.1250=0.3125\text{Relative Frequency of Marginal or Worse} = 0.1875 + 0.1250 = 0.3125

Final Answers

(a) The relative frequency distribution:

  • Good (3): 0.06250.0625
  • Acceptable (2): 0.62500.6250
  • Marginal (1): 0.18750.1875
  • Poor (0): 0.12500.1250

(b) The relative frequency that a randomly selected car will have a crash test rating of "Marginal or worse": 0.31250.3125

Let me know if you want further details or have any questions!

Here are 5 related questions to further your understanding:

  1. How is relative frequency used in probability?
  2. How would you interpret the meaning of a rating of "Acceptable" in this context?
  3. What other statistics could we calculate from this data, such as the mode or median?
  4. How does increasing the total number of cars affect the relative frequency distribution?
  5. Can you think of situations where calculating cumulative relative frequency might be useful?

Tip: Always ensure that relative frequencies sum up to 1 to verify your calculations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Relative Frequency Distribution
Probability

Formulas

Relative Frequency = (Frequency of category) / (Total number of cars)

Theorems

-

Suitable Grade Level

Grades 9-12