Math Problem Statement

there are 4 slots: slot A, B, C and D. The numbers 1, 3, 5, and 7 can be put into any of these slots. All numbers must be present in a combination, and they must be in ascending order from each slot For example, a combination could have the numbers 1 and 3 and 5 in slot A, and 7 in slot D. However, you cannot have the numbers 1 and 3 in slot B, 5 in slot D, and 7 in slot A. Another thing to note is if let's say both the numbers 5 and 7 are in slot C, 5 must come after 7 in the slot. How many possible combinations are there?

Solution

Let's break down the problem step by step.

Problem Recap:

  • There are 4 slots: A, B, C, and D.
  • We have 4 distinct numbers: 1, 3, 5, and 7.
  • The numbers must be placed in the slots in such a way that:
    • All numbers must be in ascending order according to the slot labels.
    • Within the same slot, the numbers must also appear in ascending order.

Approach:

  1. Combinatorial Choices for Slots: First, determine how to distribute the 4 numbers among the 4 slots.

    • Each number must be placed in one of the 4 slots, and since the numbers must be in ascending order both across and within slots, the order of the numbers in the slots is fixed once they are assigned to slots.
  2. Distribution of Numbers Among Slots: The problem of distributing the numbers across slots with the above constraints can be solved by counting the number of ways to partition the 4 numbers into 4 non-empty, ordered subsets.

    Let x1,x2,x3,x4x_1, x_2, x_3, x_4 be the number of elements in slots AA, BB, CC, and DD, respectively. We are required to count the number of integer solutions to the equation: x1+x2+x3+x4=4x_1 + x_2 + x_3 + x_4 = 4 where xi0x_i \geq 0 for all ii (but not all xix_i can be zero simultaneously, since each slot can hold zero or more numbers).

    This is equivalent to counting the number of non-negative integer solutions to the equation above.

  3. Computation of Combinations: The number of ways to distribute nn indistinguishable objects (numbers) into kk distinct slots (slots) is given by the "stars and bars" theorem. Here, we can use the binomial coefficient: (n+k1k1)\binom{n+k-1}{k-1} For n=4n = 4 (numbers) and k=4k = 4 (slots), the formula becomes: (4+4141)=(73)=35\binom{4+4-1}{4-1} = \binom{7}{3} = 35 This counts the number of ways to assign 4 distinct objects into 4 slots, where each slot can hold between 0 and 4 objects, maintaining the order within each slot.

Thus, the total number of valid combinations where the numbers 1, 3, 5, and 7 are placed in slots A,B,C,DA, B, C, D in ascending order is 35.

Conclusion:

There are 35 possible combinations that satisfy the given conditions.

Would you like a detailed explanation of any part of the solution or have any questions?

Here are some related questions you might consider:

  1. What if there were 5 numbers and 4 slots?
  2. How would the number of combinations change if one of the numbers must always be in a specific slot?
  3. Can you generalize the result to nn numbers and kk slots?
  4. What if the numbers must be placed in descending order across slots instead?
  5. How would adding an extra condition, like a specific slot always being non-empty, affect the count?

Tip: When dealing with combinatorial problems, it's essential to clearly identify constraints and explore how the distribution of objects can be managed within those constraints.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Binomial Coefficient
Stars and Bars Theorem

Formulas

Binomial coefficient formula: C(n+k-1, k-1)

Theorems

Stars and Bars Theorem

Suitable Grade Level

High School