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The problem asks for the cost per acre given that the Inverness Investor Group bought $6 \frac{3}{5}$ acres of land for $29,700.

### Step-by-step solution:
1. First, convert the mixed number $6 \frac{3}{5}$ to an improper fraction:
   \[
   6 \frac{3}{5} = \frac{6 \times 5 + 3}{5} = \frac{30 + 3}{5} = \frac{33}{5}
   \]
   So, the group bought $\frac{33}{5}$ acres of land.

2. To find the cost per acre, divide the total cost by the number of acres:
   \[
   \text{Cost per acre} = \frac{29700}{\frac{33}{5}} = 29700 \times \frac{5}{33} = \frac{29700 \times 5}{33}
   \]
3. Perform the multiplication:
   \[
   29700 \times 5 = 148500
   \]
4. Now, divide:
   \[
   \frac{148500}{33} = 4500
   \]

Thus, the cost per acre is **$4,500**.

Would you like further details on any part of this calculation or have any other questions?

Here are five related questions for further exploration:
1. How do you convert any mixed number to an improper fraction?
2. What would the total cost be if the group bought 10 acres at the same rate?
3. How would the cost change if the price per acre increased by 10%?
4. Can you explain how to handle division involving fractions?
5. If the group had only $25,000, how many acres could they afford at the $4,500 per acre rate?

**Tip**: When working with mixed numbers, always convert them into improper fractions for easier calculations.

The Inverness Investor Group bought 6 3/5 acres of land for $29,700. What was the cost of each acre?

Learn how to calculate the cost per acre when 6 3/5 acres of land were bought for $29,700. This problem involves converting a mixed number to an improper fraction and dividing the total cost by the total acres.

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