https://file.aiquickdraw.com/mathbot/file/17274054156581z27xm0v.jpg

To solve this problem, we need to find the translation rule used to move Triangle PQR to Triangle P'Q'R', then apply the same translation to Square STUV to determine the coordinates of point T'.

### Step 1: Determine the translation rule for Triangle PQR
By looking at the graph:
- Point P moves from \( P(3, 7) \) to \( P'(-4, 6) \).
  - Translation for \(x\): \( 3 \to -4 \) (Subtract 7)
  - Translation for \(y\): \( 7 \to 6 \) (Subtract 1)
  
Thus, the translation rule is \( (x, y) \to (x - 7, y - 1) \).

### Step 2: Apply the same translation to Square STUV
We now apply this translation to the coordinates of point T, which is currently at \( T(6, 1) \).
- Apply the translation rule \( (x, y) \to (x - 7, y - 1) \):
  - \( x: 6 - 7 = -1 \)
  - \( y: 1 - 1 = 0 \)

Therefore, the coordinates of point T' will be \( (-1, 0) \).

### Step 3: Select the correct answer
The correct answer is:
- **D. (-1, 0)**

Would you like more details or have any questions? 

Here are 5 related questions to think about:
1. What are the coordinates of point S' after the same translation?
2. How do you verify that the translation rule is consistent for all points of Triangle PQR?
3. What is the geometric meaning of a translation on the coordinate plane?
4. Can this translation be described as a vector?
5. What other transformations can be applied to shapes in the coordinate plane?

**Tip:** Always check the movement of more than one point in a translation to ensure consistency.

Triangle PQR is translated to produce Triangle P'Q'R', as shown. Using the same translation, Square STUV will be translated to produce Square S'T'U'V'. What will be the coordinates of Point T'?

Solve a geometry problem involving the translation of Triangle PQR to P'Q'R' and applying the same translation to Square STUV to find the coordinates of Point T'. Learn about the translation formula and apply it to coordinate geometry. Suitable for Grades 8-10.

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