To convert the given logarithmic equation $\log_8(6) = x - 1$ into an exponential form, you need to apply the definition of logarithms. Recall that:

$\log_b(a) = c \quad \text{is equivalent to} \quad b^c = a$

In this case, the base $b = 8$, the argument $a = 6$, and the logarithmic result $c = x - 1$.

Thus, the exponential form of the equation will be:

$8^{x - 1} = 6$

Would you like further details or have any questions about this transformation?

Here are some related questions to consider:

1. How would you solve for $x$ if required in this exponential equation?
2. What is the relationship between logarithms and exponents?
3. How does the base of a logarithm affect the corresponding exponential equation?
4. Can this exponential equation be graphed, and how would it look?
5. What are common properties of logarithms that can be useful in rewriting or simplifying equations?

Tip: When converting logarithmic equations to exponential form, remember that the base of the logarithm becomes the base of the exponent.