The given equation in the image is:

$\log_2 x = -5$

To convert this logarithmic equation into an exponential equation, recall the general logarithmic definition:

$\log_b a = c \quad \text{means} \quad a = b^c$

In this case:

$\log_2 x = -5$

This means that $x = 2^{-5}$.

Now, solving for $x$:

$x = \frac{1}{2^5} = \frac{1}{32}$

Thus, the equivalent exponential equation is:

$x = 2^{-5}$

Would you like further details or clarifications?

Here are 5 related questions to explore:

1. How do you convert any logarithmic equation to an exponential form?
2. What is the relationship between logarithms and exponents?
3. What is the value of $\log_2(32)$?
4. How would you solve for $x$ if $\log_3 x = 4$?
5. Can you explain the properties of logarithms that make solving these equations possible?

Tip: When converting from a logarithmic to an exponential equation, always remember that the base of the logarithm becomes the base of the exponent.