The equation $7^2 = 49$ is an exponential equation. To convert it into logarithmic form, we use the general rule:

$a^b = c \quad \text{can be written as} \quad \log_a c = b$

In this case:

• $a = 7$
• $b = 2$
• $c = 49$

Thus, the logarithmic form of $7^2 = 49$ is:

$\log_7 49 = 2$

So, the correct answer is:

D. $\log_7 49 = 2$

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Would you like further details on logarithmic and exponential forms or have any questions?

Here are some related questions:

1. How do you convert a logarithmic equation back to exponential form?
2. What is the logarithm of 1 in any base?
3. Can logarithms have negative values? Why or why not?
4. How do you solve logarithmic equations with different bases?
5. What is the change of base formula for logarithms?

Tip: When converting between logarithmic and exponential forms, remember that the base of the exponent becomes the base of the logarithm.