2x(4x-3)=9 quadratic equation not in standard form

The given equation is:

\[
2x(4x - 3) = 9
\]

To express this as a quadratic equation in standard form, let's simplify it step by step:

1. Expand the left side:

\[
2x(4x - 3) = 8x^2 - 6x
\]

Now the equation becomes:

\[
8x^2 - 6x = 9
\]

2. Move all terms to one side of the equation (subtract 9 from both sides):

\[
8x^2 - 6x - 9 = 0
\]

This is the quadratic equation in standard form:

\[
8x^2 - 6x - 9 = 0
\]

Would you like to go further and solve this quadratic equation, or do you have any other questions?

### 5 Related Questions:
1. How do you solve quadratic equations using the quadratic formula?
2. What are the methods to factor quadratic equations?
3. How can you determine the discriminant of a quadratic equation?
4. What does the standard form of a quadratic equation represent geometrically?
5. How can you complete the square to solve a quadratic equation?

### Tip:
Always remember, a quadratic equation in standard form is written as \( ax^2 + bx + c = 0 \), where \(a\), \(b\), and \(c\) are constants.

Learn how to convert and simplify the quadratic equation 2x(4x-3)=9 into standard form. This solution includes expanding, simplifying, and solving quadratic equations using algebraic techniques. Suitable for students in Grades 8-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation