Convert 10^-6.2 = y into equivalent logarithmic form. Don't indicate the base because it's base 10

To convert the equation \( 10^{-6.2} = y \) into its equivalent logarithmic form, we use the property of logarithms that relates an exponential equation to a logarithmic one. The property is:

\[ 10^a = b \quad \iff \quad \log(b) = a \]

Applying this to the given equation \( 10^{-6.2} = y \):

\[ 10^{-6.2} = y \quad \iff \quad \log(y) = -6.2 \]

So, the equivalent logarithmic form of the equation \( 10^{-6.2} = y \) is:

\[ \log(y) = -6.2 \]

Would you like more details or have any questions?

Here are 5 questions you might consider asking:
1. How do you solve logarithmic equations?
2. Can you explain the properties of logarithms?
3. How do you convert between exponential and logarithmic forms for different bases?
4. What are some applications of logarithms in real life?
5. How do you simplify logarithmic expressions?

**Tip:** When working with logarithms, remember that \( \log(1) = 0 \) and \( \log(10) = 1 \) for base 10 logarithms. These properties can be very helpful in simplifying logarithmic expressions.

Learn how to convert the exponential equation 10^-6.2 = y into its equivalent logarithmic form. This problem involves exponential functions and logarithms, essential topics in advanced high school mathematics.

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