Math Problem Statement
Solution
To test the convergence of the series:
we can analyze it as an alternating series (due to the factor) and check for convergence by using the Alternating Series Test (Leibniz's Test) and/or other tests if necessary.
Step 1: Applying the Alternating Series Test
For an alternating series , the series converges if:
- is positive.
- is decreasing.
- .
In this case, let:
1. Positivity
Since and are both positive for , for all .
2. Monotonic Decrease
To check if is decreasing, we could examine or analyze the derivative if it’s a continuous function. Here, as increases, both and increase, but the denominator grows faster than the numerator, suggesting that decreases.
3. Limit of as
We compute the limit: Dividing the numerator and denominator by :
Since , the series fails the Alternating Series Test.
Step 2: Applying the Divergence Test
The Divergence Test states that if , then the series diverges. Since we found: the series diverges.
Conclusion
The series diverges.
Would you like further details on any of the steps?
Here are some related questions for further exploration:
- How does the Alternating Series Test work in general?
- When should the Divergence Test be applied before other tests?
- What if the limit of goes to zero but the terms are not decreasing—does the series converge?
- How does the growth rate of compared to affect the convergence?
- Can you use other tests, like the Ratio Test, on this series?
Tip: Always check the Divergence Test as a first step; if , the series cannot converge.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Series Convergence
Alternating Series
Limits
Formulas
\( \sum_{n=1}^{\infty} (-1)^n a_n \)
Limit of \( a_n \) as \( n \to \infty \)
Theorems
Alternating Series Test (Leibniz's Test)
Divergence Test
Suitable Grade Level
College-level
Related Recommendation
Using the Ratio Test to Determine Convergence of an Alternating Series with Square Roots
Convergence of Alternating Series (-1)^n (sqrt(n)/(n+8))
Convergence Test for Series \( \sum_{n=1}^{\infty} \frac{(-1)^n \sqrt{n}}{1 + 2\sqrt{n}} \) Using the Ratio Test
Convergence of Alternating Series: (-1)^n/(n^2 sqrt(n^2 - 1))
Determine Convergence or Divergence Using the Divergence Test