Math Problem Statement

Test for convergence of the series \( \sum_{n=1}^{\infty} (-1)^n \frac{\sqrt{n}}{1 + 2\sqrt{n}} \).

Solution

To test the convergence of the series:

n=1(1)nn1+2n\sum_{n=1}^{\infty} (-1)^n \frac{\sqrt{n}}{1 + 2\sqrt{n}}

we can analyze it as an alternating series (due to the (1)n(-1)^n factor) and check for convergence by using the Alternating Series Test (Leibniz's Test) and/or other tests if necessary.

Step 1: Applying the Alternating Series Test

For an alternating series (1)nan\sum (-1)^n a_n, the series converges if:

  1. ana_n is positive.
  2. ana_n is decreasing.
  3. limnan=0\lim_{n \to \infty} a_n = 0.

In this case, let: an=n1+2na_n = \frac{\sqrt{n}}{1 + 2\sqrt{n}}

1. Positivity

Since n\sqrt{n} and 1+2n1 + 2\sqrt{n} are both positive for n1n \geq 1, an>0a_n > 0 for all n1n \geq 1.

2. Monotonic Decrease

To check if ana_n is decreasing, we could examine an+1<ana_{n+1} < a_n or analyze the derivative if it’s a continuous function. Here, as nn increases, both n\sqrt{n} and 1+2n1 + 2\sqrt{n} increase, but the denominator grows faster than the numerator, suggesting that ana_n decreases.

3. Limit of ana_n as nn \to \infty

We compute the limit: limnan=limnn1+2n\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{\sqrt{n}}{1 + 2\sqrt{n}} Dividing the numerator and denominator by n\sqrt{n}: =limn11n+2=10+2=12= \lim_{n \to \infty} \frac{1}{\frac{1}{\sqrt{n}} + 2} = \frac{1}{0 + 2} = \frac{1}{2}

Since limnan0\lim_{n \to \infty} a_n \neq 0, the series fails the Alternating Series Test.

Step 2: Applying the Divergence Test

The Divergence Test states that if limnan0\lim_{n \to \infty} a_n \neq 0, then the series diverges. Since we found: limnan=120\lim_{n \to \infty} a_n = \frac{1}{2} \neq 0 the series diverges.

Conclusion

The series n=1(1)nn1+2n\sum_{n=1}^{\infty} (-1)^n \frac{\sqrt{n}}{1 + 2\sqrt{n}} diverges.


Would you like further details on any of the steps?

Here are some related questions for further exploration:

  1. How does the Alternating Series Test work in general?
  2. When should the Divergence Test be applied before other tests?
  3. What if the limit of ana_n goes to zero but the terms are not decreasing—does the series converge?
  4. How does the growth rate of n\sqrt{n} compared to 1+2n1 + 2\sqrt{n} affect the convergence?
  5. Can you use other tests, like the Ratio Test, on this series?

Tip: Always check the Divergence Test as a first step; if limnan0\lim_{n \to \infty} a_n \neq 0, the series cannot converge.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Alternating Series
Limits

Formulas

\( \sum_{n=1}^{\infty} (-1)^n a_n \)
Limit of \( a_n \) as \( n \to \infty \)

Theorems

Alternating Series Test (Leibniz's Test)
Divergence Test

Suitable Grade Level

College-level