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To analyze the convergence of each series, let's examine each individually using appropriate convergence tests as suggested: the Ratio Test, Root Test, or Integral Test.

1. **First Series**: \(\sum_{n=0}^{\infty} \frac{n^{40} \cdot 40^n}{n!}\)
   - **Ratio Test** is useful here because we have terms involving factorials and exponential growth.
   - Applying the Ratio Test:
     \[
     \lim_{n \to \infty} \left| \frac{(n+1)^{40} \cdot 40^{n+1}}{(n+1)!} \cdot \frac{n!}{n^{40} \cdot 40^n} \right| = \lim_{n \to \infty} \frac{(n+1)^{40} \cdot 40}{(n+1) \cdot n^{40}} = 0
     \]
   - Since the limit is 0, this series **converges** by the Ratio Test.

2. **Second Series**: \(\sum_{n=0}^{\infty} n \cdot 4^{-n}\)
   - Here, each term is \(n \cdot 4^{-n} = \frac{n}{4^n}\).
   - **Ratio Test** or **Root Test** is effective for terms with exponential decay.
   - Applying the Ratio Test:
     \[
     \lim_{n \to \infty} \left| \frac{(n+1) \cdot 4^{-(n+1)}}{n \cdot 4^{-n}} \right| = \lim_{n \to \infty} \frac{n+1}{4n} = 0
     \]
   - The limit is 0, so this series **converges** by the Ratio Test.

3. **Third Series**: \(\sum_{n=2}^{\infty} \left(\frac{4n}{\ln n}\right)^n\)
   - This series has the form \(\left(\frac{4n}{\ln n}\right)^n\), where the base grows with \(n\).
   - **Root Test** is particularly suitable here because each term is raised to the \(n\)-th power.
   - Applying the Root Test:
     \[
     \lim_{n \to \infty} \sqrt[n]{\left(\frac{4n}{\ln n}\right)^n} = \lim_{n \to \infty} \frac{4n}{\ln n} = \infty
     \]
   - Since the limit is infinite, this series **diverges** by the Root Test.

4. **Fourth Series**: \(\sum_{n=0}^{\infty} \left(\frac{9n + 7}{7n + 9}\right)^n\)
   - Similar to the third series, the terms have the form \(\left(\frac{9n + 7}{7n + 9}\right)^n\).
   - Using the **Root Test** again:
     \[
     \lim_{n \to \infty} \sqrt[n]{\left(\frac{9n + 7}{7n + 9}\right)^n} = \lim_{n \to \infty} \frac{9n + 7}{7n + 9} = \frac{9}{7} > 1
     \]
   - Since the limit is greater than 1, this series **diverges** by the Root Test.

### Conclusion
- **Convergent Series**: Series 1 and Series 2.
- **Divergent Series**: Series 3 and Series 4.

Would you like more details on these tests, or have any questions about convergence?

Here are some related questions:
1. How does the Ratio Test determine convergence for factorials?
2. Why is the Root Test effective for exponential terms?
3. Can the Integral Test be applied to series involving factorials?
4. What happens if the Ratio Test yields a limit of 1?
5. Are there alternative methods to test for convergence here?

**Tip**: Use the Ratio Test when you see factorials or powers involving \(n!\).

Select ALL the series which are convergent. (Hint: Use Ratio Test, Root Test, or Integral Test)
1. \(\sum_{n=0}^{\infty} \frac{n^{40} \cdot 40^n}{n!}\)
2. \(\sum_{n=0}^{\infty} n \cdot 4^{-n}\)
3. \(\sum_{n=2}^{\infty} \left(\frac{4n}{\ln n}\right)^n\)
4. \(\sum_{n=0}^{\infty} \left(\frac{9n + 7}{7n + 9}\right)^n\)

Determine the convergence of various series using the Ratio Test, Root Test, or Integral Test. This problem involves factorial, exponential, and logarithmic functions to test for series convergence, suitable for advanced calculus students.

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