Math Problem Statement

Prove that the improper integral \(\int_{1}^{\infty} \frac{\sin x}{x} \, dx\) converges by using integration by parts and the comparison theorem.

Solution

The task is to prove that the improper integral

1sinxxdx\int_{1}^{\infty} \frac{\sin x}{x} \, dx

converges by first applying integration by parts and then using the comparison theorem mentioned in the problem.


Step 1: Integration by Parts

Using the formula for integration by parts:

udv=uvvdu\int u \, dv = uv - \int v \, du

Set:

  • u=1xu = \frac{1}{x}, so du=1x2dxdu = -\frac{1}{x^2} dx,
  • dv=sinxdxdv = \sin x \, dx, so v=cosxv = -\cos x.

Thus:

1sinxxdx=[cosxx]1+1cosxx2dx\int_{1}^{\infty} \frac{\sin x}{x} \, dx = \left[-\frac{\cos x}{x}\right]_1^\infty + \int_{1}^{\infty} \frac{\cos x}{x^2} \, dx

The first term, cosxx-\frac{\cos x}{x}, approaches zero as xx \to \infty, since cosx\cos x oscillates between -1 and 1 and xx grows without bound. Therefore:

1sinxxdx=1cosxx2dx\int_{1}^{\infty} \frac{\sin x}{x} \, dx = \int_{1}^{\infty} \frac{\cos x}{x^2} \, dx


Step 2: Convergence of the Remaining Integral

To prove the convergence of

1cosxx2dx,\int_{1}^{\infty} \frac{\cos x}{x^2} \, dx,

use the comparison theorem.

Bounding cosx/x2|\cos x / x^2|:

The absolute value of cosx\cos x satisfies cosx1|\cos x| \leq 1. Thus:

cosxx21x2.\left| \frac{\cos x}{x^2} \right| \leq \frac{1}{x^2}.

The integral 11x2dx\int_{1}^{\infty} \frac{1}{x^2} dx is a p-integral with p=2>1p = 2 > 1, so it converges. By the comparison theorem, the integral

1cosxx2dx\int_{1}^{\infty} \frac{\cos x}{x^2} \, dx

also converges.


Conclusion

Since the remaining integral converges, the original integral

1sinxxdx\int_{1}^{\infty} \frac{\sin x}{x} \, dx

also converges.


Would you like a further breakdown of any specific step or additional examples related to improper integrals? Here are some follow-up questions to consider:

  1. Can I provide more examples of integration by parts for improper integrals?
  2. Would you like further details about the comparison theorem?
  3. Do you need clarification on the behavior of oscillatory functions in improper integrals?
  4. Should I explain convergence criteria for improper integrals in more depth?
  5. Would you like a visual representation of how sinx/x\sin x / x behaves as xx \to \infty?

Tip: Always analyze the absolute value of the integrand for convergence in oscillatory improper integrals.

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Math Problem Analysis

Mathematical Concepts

Improper Integrals
Integration by Parts
Comparison Theorem
Oscillatory Functions

Formulas

Integration by parts formula: \(\int u \, dv = uv - \int v \, du\)

Theorems

Comparison Theorem for Improper Integrals

Suitable Grade Level

University Level (Calculus II or III)