Math Problem Statement

integrate 1/(sqrt(x(1 - x))) dx from 0 to 1 test the convergence

Solution

We are asked to evaluate the integral:

I=011x(1x)dxI = \int_0^1 \frac{1}{\sqrt{x(1 - x)}} \, dx

Step 1: Simplification using a substitution

Let's simplify this integral by performing a common trigonometric substitution:

Let x=sin2θx = \sin^2 \theta, so that dx=2sinθcosθdθdx = 2 \sin \theta \cos \theta \, d\theta. Notice that:

  • When x=0x = 0, θ=0\theta = 0,
  • When x=1x = 1, θ=π2\theta = \frac{\pi}{2}.

Now, we rewrite the integral in terms of θ\theta:

x(1x)=sin2θ(1sin2θ)=sin2θcos2θ=sinθcosθ\sqrt{x(1 - x)} = \sqrt{\sin^2 \theta (1 - \sin^2 \theta)} = \sqrt{\sin^2 \theta \cos^2 \theta} = \sin \theta \cos \theta

Thus, the integral becomes:

I=0π21sinθcosθ2sinθcosθdθ=20π2dθ=πI = \int_0^{\frac{\pi}{2}} \frac{1}{\sin \theta \cos \theta} \cdot 2 \sin \theta \cos \theta \, d\theta = 2 \int_0^{\frac{\pi}{2}} d\theta = \pi

Step 2: Test for Convergence

We want to check the convergence at the boundaries x=0x = 0 and x=1x = 1.

Behavior near x=0x = 0:

As x0x \to 0, the integrand behaves like:

1x since (1x)1\frac{1}{\sqrt{x}} \text{ since } (1 - x) \to 1

The integral of 1x\frac{1}{\sqrt{x}} near 0 is:

0ϵ1xdx=2ϵ\int_0^\epsilon \frac{1}{\sqrt{x}} \, dx = 2 \sqrt{\epsilon}

which converges as ϵ0\epsilon \to 0.

Behavior near x=1x = 1:

As x1x \to 1, the integrand behaves like:

11x since x1\frac{1}{\sqrt{1 - x}} \text{ since } x \to 1

The integral of 11x\frac{1}{\sqrt{1 - x}} near 1 is:

1ϵ111xdx=2ϵ\int_{1 - \epsilon}^1 \frac{1}{\sqrt{1 - x}} \, dx = 2 \sqrt{\epsilon}

which also converges as ϵ0\epsilon \to 0.

Conclusion:

Both boundaries behave well, and the integral converges. Thus, the value of the integral is:

I=πI = \pi

Would you like further details on any part of the solution? Here are some related questions to expand on this topic:

  1. What other trigonometric substitutions are useful for similar integrals?
  2. How do we handle improper integrals with more difficult boundary behavior?
  3. Can we solve this integral using a different substitution method?
  4. How does the convergence test change for more complex functions?
  5. What are the implications of this result in probability or statistics?

Tip: Trigonometric substitutions are powerful tools when dealing with square roots of quadratic expressions in integrals.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Trigonometric Substitution
Convergence of Improper Integrals

Formulas

I = ∫(1/(sqrt(x(1 - x)))) dx
Trigonometric substitution: x = sin^2(θ), dx = 2 sin(θ) cos(θ) dθ

Theorems

Convergence Test for Improper Integrals

Suitable Grade Level

College Level (Calculus II or III)