Math Problem Statement

Draw a triangle of circumradius 4 centimetres and two of the angles are 60 and 80

Solution

To draw a triangle with a circumradius of 4 cm and two angles of 60° and 80°, we need to find the lengths of its sides using the Law of Sines. Here’s the process to draw the triangle step-by-step:

Step-by-step Construction:

  1. Understand the Given Information:

    • Circumradius (R) = 4 cm
    • Angles: A=60\angle A = 60^\circ, B=80\angle B = 80^\circ
    • Since the sum of the angles in a triangle is 180°, the third angle C=1806080=40\angle C = 180^\circ - 60^\circ - 80^\circ = 40^\circ.
  2. Use the Law of Sines: The Law of Sines relates the sides of a triangle to the sine of its angles: asinA=bsinB=csinC=2R\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = 2R Where:

    • aa, bb, and cc are the lengths of the sides opposite to angles AA, BB, and CC respectively.
    • R=4R = 4 cm.

    Using the above relation: a=2RsinA=2×4×sin(60)a = 2R \cdot \sin A = 2 \times 4 \times \sin(60^\circ) b=2RsinB=2×4×sin(80)b = 2R \cdot \sin B = 2 \times 4 \times \sin(80^\circ) c=2RsinC=2×4×sin(40)c = 2R \cdot \sin C = 2 \times 4 \times \sin(40^\circ)

  3. Calculate Side Lengths: a=8×sin(60)=8×32=43cm6.93cma = 8 \times \sin(60^\circ) = 8 \times \frac{\sqrt{3}}{2} = 4\sqrt{3} \, \text{cm} \approx 6.93 \, \text{cm} b=8×sin(80)8×0.985=7.88cmb = 8 \times \sin(80^\circ) \approx 8 \times 0.985 = 7.88 \, \text{cm} c=8×sin(40)8×0.643=5.14cmc = 8 \times \sin(40^\circ) \approx 8 \times 0.643 = 5.14 \, \text{cm}

  4. Draw the Triangle:

    • Draw a line segment BCBC of length c=5.14c = 5.14 cm.
    • At point BB, use a protractor to construct an angle of 80°.
    • At point CC, construct an angle of 60°.
    • The two rays from points BB and CC will intersect at point AA.
    • Connect points AA to BB and AA to CC to complete the triangle.

Summary

You should now have a triangle with side lengths approximately 6.93 cm, 7.88 cm, and 5.14 cm, with the given angles and a circumradius of 4 cm.

Would you like more details on any of the steps?

Further Related Questions:

  1. How do you calculate the circumradius of a triangle given its side lengths?
  2. What is the Law of Sines and how is it applied in triangle problems?
  3. How to construct a triangle given its circumradius and all three angles?
  4. How does the circumcircle relate to the triangle's properties?
  5. What are the other ways to solve triangles with given angles and circumradius?

Tip: When solving triangle problems, always remember the relationship between angles and side lengths using trigonometric laws.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Triangle Construction
Law of Sines

Formulas

Law of Sines: a/sin(A) = b/sin(B) = c/sin(C) = 2R
Sum of angles in a triangle: A + B + C = 180°

Theorems

Law of Sines
Sum of Angles in a Triangle

Suitable Grade Level

Grades 9-10