In a survey, 13 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $39 and standard deviation of $16. Construct a confidence interval at a 95% confidence level.

Give your answers to one decimal place.

To construct a 95% confidence interval for the mean amount spent on a child's last birthday gift, we'll use the formula for the confidence interval of the mean:

\[
\text{CI} = \bar{x} \pm z \left(\frac{\sigma}{\sqrt{n}}\right)
\]

Where:
- $\bar{x} = 39$ is the sample mean,
- $\sigma = 16$ is the standard deviation,
- $n = 13$ is the sample size,
- $z$ is the z-value corresponding to a 95% confidence level (which is approximately 1.96).

### Step-by-step solution:

1. **Calculate

In a survey, 13 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $39 and standard deviation of $16. Construct a confidence interval at a 95% confidence level. Give your answers to one decimal place.

Construct a 95% confidence interval for the mean amount spent on a child's birthday gift. Given a sample size of 13, a mean of $39, and a standard deviation of $16, learn how to apply the confidence interval formula and interpret the result. Suitable for high school students in Grades 10-12.

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