The problem is asking for the probability of rolling a 5 on a standard six-sided die, given that the outcome is an odd number. Let's break this down step by step.

Step 1: Identify the odd numbers on the die.

A standard six-sided die has the numbers: 1, 2, 3, 4, 5, and 6. The odd numbers are:

• 1
• 3
• 5

So, the total possible outcomes for odd numbers are 3.

Step 2: Define the favorable outcome.

The question asks for the probability that the number rolled is 5, given that it is odd. Out of the 3 possible odd outcomes, only one of them is a 5.

Step 3: Calculate the conditional probability.

The probability of rolling a 5 given that the outcome is odd is the ratio of favorable outcomes (rolling a 5) to the total number of odd outcomes: $P(5 \,|\, \text{odd}) = \frac{1}{3}$

Final Answer:

The probability is $\frac{1}{3}$, so the correct answer is 1/3.

Would you like more details on how conditional probability works, or do you have any other questions?

Here are 5 related questions for further practice:

1. What is the probability of rolling an even number on a fair six-sided die?
2. If you roll two dice, what is the probability that their sum is odd?
3. What is the probability of rolling a number greater than 4 on a six-sided die?
4. How would the probability change if the die had 8 sides instead of 6?
5. What is the probability of rolling a 3 or a 5 on a standard die?

Tip: When dealing with conditional probability, always reduce your sample space to just the possible outcomes under the given condition.