Math Problem Statement

Condense the expression to a single logarithm using the properties of logarithms.

log(x)−12log(y)+7log(z)

Solution

To condense the given expression to a single logarithm, we use the properties of logarithms:

  1. Product Rule: log(a)+log(b)=log(ab)\log(a) + \log(b) = \log(a \cdot b),
  2. Quotient Rule: log(a)log(b)=log(ab)\log(a) - \log(b) = \log\left(\frac{a}{b}\right),
  3. Power Rule: klog(a)=log(ak)k \cdot \log(a) = \log(a^k).

The given expression is:

log(x)12log(y)+7log(z).\log(x) - 12\log(y) + 7\log(z).

Step 1: Apply the power rule

Rewrite 12log(y)12\log(y) as log(y12)\log(y^{12}) and 7log(z)7\log(z) as log(z7)\log(z^7):

log(x)log(y12)+log(z7).\log(x) - \log(y^{12}) + \log(z^7).

Step 2: Combine terms using the product and quotient rules

First, combine log(x)\log(x) and log(z7)\log(z^7) using the product rule:

log(x)+log(z7)=log(xz7).\log(x) + \log(z^7) = \log(x \cdot z^7).

Then subtract log(y12)\log(y^{12}) using the quotient rule:

log(xz7)log(y12)=log(xz7y12).\log(x \cdot z^7) - \log(y^{12}) = \log\left(\frac{x \cdot z^7}{y^{12}}\right).

Final Answer:

log(xz7y12).\log\left(\frac{x \cdot z^7}{y^{12}}\right).


Would you like a step-by-step breakdown of any part of the process?

5 Related Questions:

  1. What are the properties of logarithms and when are they used?
  2. How do you expand logarithmic expressions?
  3. What is the difference between natural logarithms and common logarithms?
  4. How would you handle an expression like 2log(a)3log(b)+log(c)2\log(a) - 3\log(b) + \log(c)?
  5. What happens if there are negative numbers inside a logarithm?

Tip:

Always check that the arguments of logarithms are positive before simplifying, as logarithms are undefined for non-positive values.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Properties of Logarithms

Formulas

Product Rule: log(a) + log(b) = log(a * b)
Quotient Rule: log(a) - log(b) = log(a / b)
Power Rule: k * log(a) = log(a^k)

Theorems

Properties of Logarithms

Suitable Grade Level

Grades 8-10