To compute the expression \( \frac{1}{n} + \frac{n + 1}{n} \), let's simplify it step-by-step.

1. Start by distributing the denominator \(n\) across both terms in the fraction:

\[
\frac{1}{n} + \frac{n + 1}{n}
\]

2. Separate the terms in the second fraction:

\[
\frac{1}{n} + \frac{n}{n} + \frac{1}{n}
\]

3. Simplify the fraction \( \frac{n}{n} \) to 1 (since any number divided by itself, except 0, equals 1):

\[
\frac{1}{n} + 1 + \frac{1}{n}
\]

4. Combine like terms:

\[
1 + \frac{1}{n} + \frac{1}{n} = 1 + \frac{2}{n}
\]

So, the simplified expression is:

\[
1 + \frac{2}{n}
\]

This is the result of computing \( \frac{1}{n} + \frac{n + 1}{n} \).

### Would you like more details or have any questions?

#### Here are 5 related questions to expand your understanding:

1. How would you compute the expression \( \frac{a}{b} + \frac{c}{d} \) in general?
2. What is the result of \( \frac{1}{n} - \frac{n + 1}{n} \)?
3. How does changing \(n\) affect the value of \(1 + \frac{2}{n}\)?
4. Can you rewrite the expression \(1 + \frac{2}{n}\) in a single fraction?
5. How would the expression change if it were \( \frac{1}{n} \cdot \frac{n+1}{n} \) instead?

#### **Tip:** When working with fractions, always try to simplify by finding common denominators or factoring out terms.

Learn how to compute the expression 1/n + (n + 1)/n with a step-by-step simplification. This problem involves fractions and operations with fractions, suitable for students in Grades 7-9.

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