Math Problem Statement

double integral of 1/(1+x*y), with x between 0 and 1, y between 0 and 1

Solution

To compute the double integral of 11+xy\frac{1}{1 + xy} with xx ranging from 0 to 1 and yy ranging from 0 to 1, we can set up the integral as follows:

Region11+xydA\iint_{\text{Region}} \frac{1}{1 + xy} \, dA

This can be written as:

010111+xydxdy\int_{0}^{1} \int_{0}^{1} \frac{1}{1 + xy} \, dx \, dy

We can first integrate with respect to xx and then with respect to yy. So, let's proceed with the integration:

  1. Integrate with respect to xx:

0111+xydx\int_{0}^{1} \frac{1}{1 + xy} \, dx

For this inner integral, we use the substitution u=1+xyu = 1 + xy, hence du=ydxdu = y \, dx. When x=0x = 0, u=1u = 1, and when x=1x = 1, u=1+yu = 1 + y. Therefore,

dx=duydx = \frac{du}{y}

Substituting into the integral, we get:

11+y1uduy=1y11+y1udu=1y[lnu]11+y\int_{1}^{1+y} \frac{1}{u} \cdot \frac{du}{y} = \frac{1}{y} \int_{1}^{1+y} \frac{1}{u} \, du = \frac{1}{y} \left[ \ln u \right]_{1}^{1+y}

Evaluating the definite integral:

1y(ln(1+y)ln1)=ln(1+y)y\frac{1}{y} \left( \ln(1 + y) - \ln 1 \right) = \frac{\ln(1 + y)}{y}

  1. Integrate with respect to yy:

Now we need to integrate ln(1+y)y\frac{\ln(1 + y)}{y} with respect to yy from 0 to 1:

01ln(1+y)ydy\int_{0}^{1} \frac{\ln(1 + y)}{y} \, dy

This integral is known as the Euler integral of the second kind and can be solved by recognizing it as the dilogarithm function, specifically Li2\text{Li}_2:

01ln(1+y)ydy=Li2(2)Li2(1)=π26\int_{0}^{1} \frac{\ln(1 + y)}{y} \, dy = \text{Li}_2(2) - \text{Li}_2(1) = \frac{\pi^2}{6}

Putting it all together, the value of the double integral is:

010111+xydxdy=π26\int_{0}^{1} \int_{0}^{1} \frac{1}{1 + xy} \, dx \, dy = \frac{\pi^2}{6}

Summary

The double integral of 11+xy\frac{1}{1 + xy} over the region where xx and yy range from 0 to 1 is π26\frac{\pi^2}{6}.

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Related Questions

  1. How do you evaluate the double integral RegionexydA\iint_{\text{Region}} e^{xy} \, dA over the same region?
  2. What is the meaning of the dilogarithm function Li2\text{Li}_2?
  3. How does the substitution method help in evaluating integrals?
  4. Can you explain the steps to compute 01ln(1+y)ydy\int_{0}^{1} \frac{\ln(1 + y)}{y} \, dy in more detail?
  5. How would you evaluate the triple integral of 11+xyz\frac{1}{1 + x y z} over 0x,y,z10 \leq x, y, z \leq 1?
  6. What is the significance of the Euler integral of the second kind in mathematics?
  7. How do you determine the bounds for double integrals in different regions?
  8. How does changing the order of integration affect the result of a double integral?

Tip

Understanding the relationship between integrals and known functions, like the dilogarithm, can simplify complex integral computations.

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Math Problem Analysis

Mathematical Concepts

Double Integrals
Substitution Method
Euler Integral of the Second Kind

Formulas

Integral of ln(1 + y)/y

Theorems

Evaluation of Double Integrals

Suitable Grade Level

Advanced Mathematics