Math Problem Statement

Homework:Homework 6 Question 54, 6.7.29 HW Score: 90.91%, 50 of 55 points Points: 0 of 1

Skip to Main content Question 1 Question 2 Question 3 Question 4 Question 5 Question 6 Question 7 Question 8 Question 9 Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Question 17 Question 18 Question 19 Question 20 Question 21 Question 22 Question 23 Question 24 Question 25 Question 26 Question 27 Question 28 Question 29 Question 30 Question 31 Question 32 Question 33 Question 34 Question 35 Question 36 Question 37 Question 38 Question 39 Question 40 Question 41 Question 42 Question 43 Question 44 Question 45 Question 46 Question 47 Question 48 Question 49 Question 50 Question 51 Question 52 Question 53 Question 54 Question 55 Question content area top Part 1 Which of the two rates would yield the larger amount in 1​ year: 11​% compounded semiannually or 10.8​% compounded daily​? Question content area bottom Part 1 Which of the two rates would yield the larger amount in 1​ year? 10.8 % compounded daily 10.8 % compounded daily 11 % compounded semiannually 11 % compounded semiannually Which of the two rates would yield the larger amount in 1 year? Help me solve this View an example Textbook

Solution

To solve this problem, we need to compare two different interest rates that are compounded differently:

  1. 11% compounded semiannually
  2. 10.8% compounded daily

The general formula for compound interest is:

A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}

Where:

  • AA is the final amount
  • PP is the principal (initial investment)
  • rr is the annual interest rate (expressed as a decimal)
  • nn is the number of times the interest is compounded per year
  • tt is the time the money is invested or borrowed for, in years

Step 1: Calculate for 11% compounded semiannually

For the 11% compounded semiannually, the interest is compounded twice a year, so n=2n = 2.

  • r=0.11r = 0.11
  • n=2n = 2
  • t=1t = 1

The formula becomes:

A=P(1+0.112)2×1A = P \left(1 + \frac{0.11}{2}\right)^{2 \times 1}

Simplify:

A=P(1+0.055)2A = P \left(1 + 0.055\right)^2 A=P×(1.055)2A = P \times (1.055)^2 A=P×1.113025A = P \times 1.113025

So, the amount after 1 year is P×1.113025P \times 1.113025.

Step 2: Calculate for 10.8% compounded daily

For the 10.8% compounded daily, the interest is compounded 365 times a year, so n=365n = 365.

  • r=0.108r = 0.108
  • n=365n = 365
  • t=1t = 1

The formula becomes:

A=P(1+0.108365)365×1A = P \left(1 + \frac{0.108}{365}\right)^{365 \times 1}

Simplify:

A=P(1+0.00029589)365A = P \left(1 + 0.00029589\right)^{365} A=P×(1.00029589)365A = P \times (1.00029589)^{365} A=P×1.113492A = P \times 1.113492

So, the amount after 1 year is P×1.113492P \times 1.113492.

Step 3: Compare the two results

  • 11% compounded semiannually yields P×1.113025P \times 1.113025.
  • 10.8% compounded daily yields P×1.113492P \times 1.113492.

Thus, 10.8% compounded daily yields a slightly larger amount after 1 year compared to 11% compounded semiannually.


Do you need more details on any step or clarification?

Related Questions:

  1. How do you calculate compound interest for monthly compounding?
  2. How do interest rates affect investments over time?
  3. What is the formula for continuous compounding?
  4. What happens to the final amount as the number of compounding periods increases?
  5. How would the results change if the time period was extended to 5 years?

Tip: For comparing compounded rates, remember that the more frequently interest is compounded, the higher the final amount will be, even if the nominal rate is lower.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth
Finance

Formulas

A = P(1 + r/n)^(nt)

Theorems

Compound interest theorem

Suitable Grade Level

Grades 9-12