Math Problem Statement

In this exercise we will arrive at a composite formula for the trapezoidal rule, and study its error. We first divide the interval [π‘Ž, 𝑏] into 𝑛 segments, each of length β„Ž = 1/𝑛, and set π‘₯_𝑖 = π‘–β„Ž,𝑖 = 0, . . . , 𝑛. a) Show that the composite trapezoidal rule takes the form 𝑇_𝑛 [𝑓 ] (π‘Ž, 𝑏) = βˆ‘οΈ^π‘›βˆ’1 _ 𝑖=0 𝑇 [𝑓 ] (π‘₯_𝑖, π‘₯_𝑖+1) = β„Ž/2(𝑓 (π‘₯_0) + 𝑓 (π‘₯_𝑛)) + β„Žβˆ‘οΈ^π‘›βˆ’1 _𝑖=1 𝑓 (π‘₯_𝑖).

Solution

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Math Problem Analysis

Mathematical Concepts

Numerical Integration
Composite Trapezoidal Rule
Calculus

Formulas

Composite Trapezoidal Rule: T_n[f](a, b) = (h/2)(f(x_0) + f(x_n)) + h * Ξ£(f(x_i), i=1 to n-1)
Interval Division: h = (b - a)/n
Trapezoidal Rule for subinterval: T[f](x_i, x_{i+1}) = (h/2) * (f(x_i) + f(x_{i+1}))

Theorems

Trapezoidal Rule Error Analysis
Fundamental Theorem of Calculus

Suitable Grade Level

Undergraduate (Calculus, Numerical Methods)