Math Problem Statement

For f left parenthesis x right parenthesis equals 5 x plus 7 and g left parenthesis x right parenthesis equals x squared comma find the following composite functions and state the domain of each. ​(a)  fcircleg         ​ (b)  gcirclef           ​ (c)  fcirclef            ​ (d)  gcircleg

Solution

Given the functions f(x)=5x+7f(x) = 5x + 7 and g(x)=x2g(x) = x^2, let's find the composite functions and their domains:

(a) (fg)(x)(f \circ g)(x)

This represents f(g(x))f(g(x)), which means we substitute g(x)g(x) into f(x)f(x): (fg)(x)=f(g(x))=f(x2)=5(x2)+7=5x2+7.(f \circ g)(x) = f(g(x)) = f(x^2) = 5(x^2) + 7 = 5x^2 + 7.

Domain of (fg)(f \circ g):
Since g(x)=x2g(x) = x^2 has a domain of all real numbers R\mathbb{R}, and the expression 5x2+75x^2 + 7 is defined for all real numbers, the domain of (fg)(x)(f \circ g)(x) is also all real numbers: Domain: (,).\text{Domain: } (-\infty, \infty).

(b) (gf)(x)(g \circ f)(x)

This represents g(f(x))g(f(x)), which means we substitute f(x)f(x) into g(x)g(x): (gf)(x)=g(f(x))=g(5x+7)=(5x+7)2.(g \circ f)(x) = g(f(x)) = g(5x + 7) = (5x + 7)^2.

Domain of (gf)(g \circ f):
Since f(x)=5x+7f(x) = 5x + 7 has a domain of all real numbers R\mathbb{R}, and the expression (5x+7)2(5x + 7)^2 is defined for all real numbers, the domain of (gf)(x)(g \circ f)(x) is also all real numbers: Domain: (,).\text{Domain: } (-\infty, \infty).

(c) (ff)(x)(f \circ f)(x)

This represents f(f(x))f(f(x)), which means we substitute f(x)f(x) into itself: (ff)(x)=f(f(x))=f(5x+7)=5(5x+7)+7=25x+35+7=25x+42.(f \circ f)(x) = f(f(x)) = f(5x + 7) = 5(5x + 7) + 7 = 25x + 35 + 7 = 25x + 42.

Domain of (ff)(f \circ f):
Since f(x)=5x+7f(x) = 5x + 7 has a domain of all real numbers R\mathbb{R}, and the expression 25x+4225x + 42 is defined for all real numbers, the domain of (ff)(x)(f \circ f)(x) is also all real numbers: Domain: (,).\text{Domain: } (-\infty, \infty).

(d) (gg)(x)(g \circ g)(x)

This represents g(g(x))g(g(x)), which means we substitute g(x)g(x) into itself: (gg)(x)=g(g(x))=g(x2)=(x2)2=x4.(g \circ g)(x) = g(g(x)) = g(x^2) = (x^2)^2 = x^4.

Domain of (gg)(g \circ g):
Since g(x)=x2g(x) = x^2 has a domain of all real numbers R\mathbb{R}, and the expression x4x^4 is defined for all real numbers, the domain of (gg)(x)(g \circ g)(x) is also all real numbers: Domain: (,).\text{Domain: } (-\infty, \infty).

Summary of Composite Functions and Their Domains

  1. (fg)(x)=5x2+7(f \circ g)(x) = 5x^2 + 7, Domain: (,)(-\infty, \infty)
  2. (gf)(x)=(5x+7)2(g \circ f)(x) = (5x + 7)^2, Domain: (,)(-\infty, \infty)
  3. (ff)(x)=25x+42(f \circ f)(x) = 25x + 42, Domain: (,)(-\infty, \infty)
  4. (gg)(x)=x4(g \circ g)(x) = x^4, Domain: (,)(-\infty, \infty)

Would you like a more detailed explanation of any of these?

Here are 5 related questions for further exploration:

  1. What is the range of each composite function?
  2. How do you determine the domain of a composite function in general?
  3. What happens if one of the functions has a restricted domain?
  4. Can you find the inverse of any of these composite functions?
  5. How would the domains change if g(x)g(x) were x\sqrt{x} instead of x2x^2?

Tip: When finding the domain of a composite function, always ensure that the input of the inner function is within its domain and that the resulting value is within the domain of the outer function.

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Math Problem Analysis

Mathematical Concepts

Composite Functions
Polynomials
Domain of Functions

Formulas

f(x) = 5x + 7
g(x) = x^2
f ∘ g(x) = f(g(x))
g ∘ f(x) = g(f(x))

Theorems

Function Composition

Suitable Grade Level

Grades 10-12