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The given ratio table starts with the ratio \( 6:11 \). The objective is to complete the missing values while keeping the ratio consistent across all rows.

### Steps:
- The ratio between 6 and 11 is \( \frac{6}{11} \). This will help us scale the numbers in the first column to find the corresponding values in the second column.

#### First row:
- Given: \( 6:11 \)
  Already provided.

#### Second row:
- Multiply both sides of the ratio \( 6:11 \) by 2 (since \( 12 = 6 \times 2 \)):
  \[
  \frac{12}{x} = \frac{6}{11} \quad \text{which gives} \quad x = 11 \times 2 = 22
  \]
  So, \( 12:22 \).

#### Third row:
- To find the missing value corresponding to 30, multiply the ratio \( 6:11 \) by 5 (since \( 30 = 6 \times 5 \)):
  \[
  \frac{30}{x} = \frac{6}{11} \quad \text{which gives} \quad x = 11 \times 5 = 55
  \]
  So, \( 30:55 \).

#### Fourth row:
- Already provided: \( 36:66 \).

#### Fifth row:
- Multiply the ratio \( 6:11 \) by 8 (since \( 48 = 6 \times 8 \)):
  \[
  \frac{48}{x} = \frac{6}{11} \quad \text{which gives} \quad x = 11 \times 8 = 88
  \]
  So, \( 48:88 \).

### Completed ratio table:
\[
\begin{array}{|c|c|}
\hline
6 & 11 \\
12 & 22 \\
30 & 55 \\
36 & 66 \\
48 & 88 \\
\hline
\end{array}
\]

Would you like more details or have any questions about this solution?

Here are some related questions for practice:
1. What is the value of \( x \) in the ratio \( 18:x = 6:11 \)?
2. If the ratio is \( 6:11 \), what would the corresponding value for 60 be?
3. How would you find the missing value for a ratio table where the first column increases by 7 instead of 6?
4. Can you express the ratio \( 66:36 \) in its simplest form?
5. What happens to the ratio if both terms are multiplied by a fraction?

**Tip:** Ratios are scaled proportionally, so multiplying both terms by the same number keeps the ratio consistent.

Complete the ratio table starting with the ratio 6:11 and find the corresponding values for the other numbers.

Learn how to complete a ratio table starting with the ratio 6:11. This involves proportional scaling and solving for missing values. The problem helps students understand ratios and proportionality, ideal for Grades 6-8.

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