Math Problem Statement

Leckrone Exam 2 F2024C.pdf

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Find the complementary solution and the form of the particular solution, but DO NOT solve for the constants in the particular solution: y''-7y'+12y=x^5e^4x

Solution

To solve the differential equation y7y+12y=x5e4xy'' - 7y' + 12y = x^5 e^{4x}, we need to:

  1. Find the complementary solution, ycy_c, for the associated homogeneous equation.
  2. Identify the form of the particular solution, ypy_p, for the non-homogeneous part, without solving for constants.

Step 1: Complementary Solution

The associated homogeneous equation is: y7y+12y=0y'' - 7y' + 12y = 0 To find ycy_c, we solve the characteristic equation: r27r+12=0r^2 - 7r + 12 = 0 This factors as: (r3)(r4)=0(r - 3)(r - 4) = 0 giving roots r=3r = 3 and r=4r = 4. Therefore, the complementary solution is: yc=C1e3x+C2e4xy_c = C_1 e^{3x} + C_2 e^{4x} where C1C_1 and C2C_2 are constants.

Step 2: Form of the Particular Solution

Since the right-hand side of the equation is x5e4xx^5 e^{4x}, we apply the method of undetermined coefficients. The exponential term e4xe^{4x} suggests we try a particular solution of the form: yp=xm(A5x5+A4x4+A3x3+A2x2+A1x+A0)e4xy_p = x^m (A_5 x^5 + A_4 x^4 + A_3 x^3 + A_2 x^2 + A_1 x + A_0)e^{4x} However, e4xe^{4x} is already part of the complementary solution, so we increase the multiplicity by multiplying by x2x^2.

Thus, the form of the particular solution is: yp=x2(A5x5+A4x4+A3x3+A2x2+A1x+A0)e4xy_p = x^2 (A_5 x^5 + A_4 x^4 + A_3 x^3 + A_2 x^2 + A_1 x + A_0)e^{4x} where A0,A1,A2,A3,A4,A_0, A_1, A_2, A_3, A_4, and A5A_5 are constants to be determined.

In summary:

  • Complementary solution: yc=C1e3x+C2e4xy_c = C_1 e^{3x} + C_2 e^{4x}
  • Form of particular solution: yp=x2(A5x5+A4x4+A3x3+A2x2+A1x+A0)e4xy_p = x^2 (A_5 x^5 + A_4 x^4 + A_3 x^3 + A_2 x^2 + A_1 x + A_0)e^{4x}

Would you like more details on how to determine mm and why we chose this form for ypy_p?


Related Questions

  1. How would we solve for the constants A0,A1,,A5A_0, A_1, \ldots, A_5 in the particular solution?
  2. What if the characteristic roots had included r=4r = 4 with multiplicity 2?
  3. How does the choice of form for ypy_p change if the right-hand side is x3e4xx^3 e^{4x} instead of x5e4xx^5 e^{4x}?
  4. Can we apply the method of undetermined coefficients if the right-hand side includes sin(4x)\sin(4x)?
  5. How would the complementary solution change if the characteristic polynomial had complex roots?

Tip

When choosing a form for ypy_p, always check if terms overlap with the complementary solution. If they do, increase the multiplicity by multiplying by xx to ensure linear independence.

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Math Problem Analysis

Mathematical Concepts

Differential Equations
Complementary Solution
Particular Solution
Method of Undetermined Coefficients

Formulas

Characteristic equation for complementary solution: r^2 - 7r + 12 = 0
Form of particular solution with exponential term: y_p = x^m(A_5 x^5 + A_4 x^4 + A_3 x^3 + A_2 x^2 + A_1 x + A_0)e^{4x}

Theorems

Method of Undetermined Coefficients

Suitable Grade Level

Undergraduate (Engineering or Applied Mathematics)