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Part 1
The populations of Cities A and B are 1.9 times 10 Superscript 5 and 1 comma 065 comma 000​, respectively. The population of City C is twice the population of City B.
The population of City C is how many times the population of City​ A?

To solve this, we need to compare the populations of City C and City A.

### Step 1: Population of City C
City C's population is given as twice the population of City B. The population of City B is:
\[
1,065,000
\]
So, the population of City C is:
\[
2 \times 1,065,000 = 2,130,000
\]

### Step 2: Population of City A
The population of City A is given as:
\[
1.9 \times 10^5 = 190,000
\]

### Step 3: How many times the population of City A is City C?
We now divide the population of City C by the population of City A:
\[
\frac{\text{Population of City C}}{\text{Population of City A}} = \frac{2,130,000}{190,000}
\]

Simplifying:
\[
\frac{2,130,000}{190,000} = 11.21
\]

Thus, the population of City C is **11.21 times** the population of City A.

Would you like more details on this or have any further questions?

Here are 5 related questions:
1. What would be the population ratio if City C was 3 times the population of City B?
2. If City A's population doubled, how would the comparison change?
3. What percentage of City B's population is City A's population?
4. How many more people does City C have compared to City A?
5. If City B's population increases by 10%, what is the new population of City C?

**Tip:** When comparing populations, always ensure units and values are expressed in similar terms to avoid confusion.

The populations of Cities A and B are 1.9 times 10^5 and 1,065,000, respectively. The population of City C is twice the population of City B. The population of City C is how many times the population of City A?

Learn how to compare the populations of Cities A, B, and C. This problem involves finding how many times the population of City C is larger than City A using ratios and basic arithmetic. Suitable for students in Grades 6-8.

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