The cost of 'A' is 40% less than the cost of 'B'. But the cost of 'B' is 40% more, than that of 'C'. Determine which one is costlier 'A' or 'C' and by what %? 

Let's analyze the given problem step by step.

### 1. Relationship between the costs of A, B, and C:
- The cost of A is 40% less than the cost of B.
- The cost of B is 40% more than the cost of C.

### 2. Expressing the costs mathematically:
Let:
- $ C_C $ be the cost of C.
- $ C_B $ be the cost of B.
- $ C_A $ be the cost of A.

#### For B and C:
- $ C_B = C_C + 0.4C_C = 1.4C_C $ 

#### For A and B:
- $ C_A = C_B - 0.4C_B = 0.6C_B $

### 3. Substitute the value of $ C_B $ in the equation for $ C_A $:
- $ C_A = 0.6 \times 1.4C_C $
- $ C_A = 0.84C_C $

### 4. Conclusion:
The cost of A is 84% of the cost of C.

This means that $ C_A $ is **16% less** than $ C_C $. 

### Final Answer:
- **C** is costlier than **A** by **16%**.

Would you like any further details or have any questions?

Here are some related questions to consider:
1. If the cost of C is $100, what are the costs of A and B?
2. How would the problem change if the cost of A was 30% less than the cost of B?
3. What would happen if the cost of B was 50% more than that of C?
4. Can you find a general formula for the percentage difference between A and C for any percentage differences?
5. What if A was 20% more expensive than B, and B was 20% more expensive than C?

**Tip:** When dealing with percentage increases or decreases, it's helpful to express the original and final amounts as multiples of each other to simplify comparisons.

The cost of 'A' is 40% less than the cost of 'B'. But the cost of 'B' is 40% more than that of 'C'. Determine which one is costlier 'A' or 'C' and by what %?

Determine whether A or C is costlier by 16% using percentage and cost comparison. This problem involves understanding how to calculate percentage increases and decreases, ideal for students in Grades 8-10.

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