Math Problem Statement

a hanging ball of 0.45 kg is moving in an horizontal cyclican route with a stable velocity of 4m/s. the lenght of the rope it is hanging from is 1.8m. at angle what is the ball moving from the y axis?

Solution

To determine the angle θ\theta that the ball makes with the vertical yy-axis while it is moving in a horizontal circular path, we can use the following approach:

Step 1: Identify the forces acting on the ball

  • The tension TT in the rope.
  • The gravitational force mgmg acting downward, where mm is the mass of the ball and gg is the acceleration due to gravity.
  • The centripetal force FcF_c that keeps the ball moving in a circular path, which is provided by the horizontal component of the tension.

Step 2: Analyze the components of the forces

Let the angle θ\theta be the angle between the rope and the vertical axis (i.e., the yy-axis).

  1. Vertical component of the tension: Ty=Tcosθ=mgT_y = T \cos\theta = mg

  2. Horizontal component of the tension (providing the centripetal force): Tx=Tsinθ=mv2rT_x = T \sin\theta = \frac{mv^2}{r} Here, v=4m/sv = 4 \, \text{m/s} is the speed of the ball, and r=Lsinθr = L \sin\theta is the horizontal distance from the pivot point to the ball, where L=1.8mL = 1.8 \, \text{m} is the length of the rope.

Step 3: Use the equations to solve for θ\theta

We have the following system of equations:

  1. Tcosθ=mgT \cos\theta = mg
  2. Tsinθ=mv2LsinθT \sin\theta = \frac{mv^2}{L\sin\theta}

Dividing these two equations to eliminate TT: sinθcosθ=v2gL\frac{\sin\theta}{\cos\theta} = \frac{v^2}{gL} tanθ=v2gL\tan\theta = \frac{v^2}{gL}

Step 4: Calculate θ\theta

Now plug in the values: tanθ=429.81×1.8=1617.6580.906\tan\theta = \frac{4^2}{9.81 \times 1.8} = \frac{16}{17.658} \approx 0.906

Finally, find θ\theta using the arctan (inverse tangent) function: θ=arctan(0.906)42.17\theta = \arctan(0.906) \approx 42.17^\circ

Final Answer

The ball is moving at an angle of approximately 42.1742.17^\circ from the vertical yy-axis.

Would you like further details or have any questions? Here are five related questions:

  1. How would the angle change if the mass of the ball were doubled?
  2. What would happen to the angle if the velocity of the ball were halved?
  3. How does the length of the rope affect the angle for the same speed?
  4. What would be the tension in the rope at this angle?
  5. How would the motion change if the rope were replaced with a massless string?

Tip: Understanding the relationship between tension and the components of motion is crucial when dealing with circular motion problems.

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Math Problem Analysis

Mathematical Concepts

Circular motion
Trigonometry

Formulas

Centripetal force formula
Trigonometric functions

Theorems

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Suitable Grade Level

High school