To solve this circuit using the Superposition Theorem, we need to consider each independent source (current or voltage source) one at a time and "turn off" the others (replace voltage sources with a short circuit and current sources with an open circuit). Then, we calculate the current due to each individual source and sum the results.

Here’s a step-by-step breakdown of how to approach this:

Step 1: Turn off the 6A current source and analyze the effect of the 3A current source

• Replace the 6A current source with an open circuit (because a current source is turned off by opening the circuit).
• Calculate the current caused by the 3A current source.

Step 2: Turn off the 3A current source and analyze the effect of the 6A current source

• Replace the 3A current source with an open circuit.
• Calculate the current caused by the 6A current source.

Step 3: Sum the individual currents

• After calculating the individual contributions, sum them to find the total current $i$.

Would you like me to continue with the calculations for each case, or is there anything specific you'd like to clarify first?