The diagram shows a circle with center $O$, and angles marked at various points. Let's break down the information provided:

1. Given Information:

   • $\angle POS = 50^\circ$.
   • $\angle POQ = x^\circ + 10^\circ$.
   • $\angle QOR = 100^\circ$.
   • $\angle ROS = x^\circ$.
   • The points $P, Q, R, S$ lie on the circumference of the circle.

2. Finding the Relationship: Since $P, Q, R,$ and $S$ lie on the circle and the lines $PO$, $QO$, $RO$, and $SO$ are radii of the circle, the angles at the center $O$ subtend arcs on the circle. The sum of the angles around point $O$ should be $360^\circ$.

3. Equation Setup: Given the angles around point $O$: $(x + 10)^\circ + 100^\circ + x^\circ + 50^\circ = 360^\circ.$

4. Simplifying the Equation: Combine like terms: $2x + 160 = 360.$

5. Solve for $x$: $2x = 360 - 160,$ $2x = 200,$ $x = 100.$

Answer:

The value of $x$ is $100^\circ$.

Would you like further details or have any questions?

Related Questions:

1. What are the properties of angles subtended by the same arc at the center of a circle?
2. How do the angles at the center and circumference of a circle relate to each other?
3. Can this problem be solved using the properties of cyclic quadrilaterals?
4. How would the problem change if one of the angles were marked differently?
5. What other types of problems involve angles in circles?

Tip: In circle geometry, the sum of the angles around a point is always $360^\circ$. This property can be used to set up equations when working with central angles.