The given equation is:

\[
(x + 3)^2 + (y - 0)^2 = 16
\]

This equation represents a circle in the coordinate plane. The general form of a circle's equation is:

\[
(x - h)^2 + (y - k)^2 = r^2
\]

Where:
- \((h, k)\) is the center of the circle.
- \(r\) is the radius of the circle.

### For your equation:
- The center \((h, k)\) is \((-3, 0)\).
- The radius \(r\) is \(\sqrt{16} = 4\).

### Summary:
- **Center**: \((-3, 0)\)
- **Radius**: \(4\)

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. How do you graph a circle given its equation?
2. What is the equation of a circle with a different center but the same radius?
3. How do you find the equation of a tangent line to this circle at a specific point?
4. How does the equation change if the circle is translated 2 units up?
5. How can you derive the equation of a circle given three points on the circle?

**Tip:** Always remember to square the radius when writing the equation of a circle.

Explore the equation of a circle (x + 3)^2 + (y - 0)^2 = 16. Learn about its center, radius, and how to interpret circle equations in coordinate geometry. Suitable for Grades 9-12 students.

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