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The problem presented in the image is as follows:

**Problem 10:**

Maria and Lea are selling cheesecakes for a school fundraiser. Customers can buy French silk cheesecakes and apple cheesecakes. 
- Maria sold 12 French silk cheesecakes and 4 apple cheesecakes for a total of \$82.
- Lea sold 7 French silk cheesecakes and 14 apple cheesecakes for a total of \$152.

The goal is to find the cost of one French silk cheesecake and one apple cheesecake.

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Let:
- $ x $ represent the cost of one French silk cheesecake.
- $ y $ represent the cost of one apple cheesecake.

We can form the following system of linear equations based on the information given:

1. $ 12x + 4y = 82 $  (from Maria's sales)
2. $ 7x + 14y = 152 $  (from Lea's sales)

### Solving the system of equations:

#### Step 1: Simplify the second equation
The second equation can be simplified by dividing all terms by 7:

\[
x + 2y = 152 / 7 = 21.71
\]


Maria and Lea are selling cheesecakes for a school fundraiser. Customers can buy French silk cheesecakes and apple cheesecakes. Maria sold 12 French silk cheesecakes and 4 apple cheesecakes for a total of $82. Lea sold 7 French silk cheesecakes and 14 apple cheesecakes for a total of $152. Find the cost of each cheesecake.

Learn how to solve a system of linear equations to find the cost of French silk and apple cheesecakes sold in a school fundraiser. This problem covers essential algebra concepts and solving techniques, suitable for students in Grades 8-10.

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