Math Problem Statement

A = {1,1} then A X A X A is

Solution

The set A={1,1}A = \{1, 1\} actually contains only one distinct element, which is 11. In set theory, duplicate elements are not counted, so this set simplifies to:

A={1}A = \{1\}

Now, if we take the Cartesian product of AA with itself three times, i.e., A×A×AA \times A \times A, we are essentially finding the set of all ordered triplets (a,b,c)(a, b, c) where each of aa, bb, and cc is an element of AA.

Since A={1}A = \{1\}, every element in A×A×AA \times A \times A will be the triplet (1,1,1)(1, 1, 1). Therefore,

A×A×A={(1,1,1)}A \times A \times A = \{(1, 1, 1)\}

Summary:

The Cartesian product A×A×AA \times A \times A is simply {(1,1,1)}\{(1, 1, 1)\}.

Would you like further explanation or clarification? Here are 5 related questions you might find helpful:

  1. What is the Cartesian product of two sets, A×BA \times B?
  2. How do you find the number of elements in a Cartesian product of sets?
  3. Can a set contain duplicate elements, and how does this affect its size?
  4. How do you find the Cartesian product of an empty set with any set?
  5. What happens when you take the Cartesian product of a set with itself multiple times?

Tip: The Cartesian product of two sets results in a set of all possible ordered pairs formed by taking one element from each set.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product

Formulas

A × A × A = {(a, b, c) | a, b, c ∈ A}

Theorems

Set Theory - Duplicate elements are not counted in a set
Cartesian Product of sets

Suitable Grade Level

Grades 6-8