Math Problem Statement

What is the value of ax , the x -component of the object’s acceleration?

What is the value of ax, the x-component of the object’s acceleration?

Solution

To find the xx-component of the object's acceleration, we need to analyze the forces in the horizontal (x) direction, and then apply Newton's second law:

F=maF = ma where:

  • FxF_x is the total force in the xx-direction.
  • mm is the mass of the object.
  • axa_x is the xx-component of acceleration.

Let's break down the forces in the xx-direction based on the diagram:

Forces in the xx-direction:

  1. 1.0 N: This force is already along the positive xx-axis, so it contributes +1.0N+1.0 \, \text{N}.
  2. 5.0 N at an angle of 20°: We need the xx-component of this force. Using the cosine of the angle: Fx,5.0N=5.0cos(20)F_{x, 5.0\,N} = 5.0 \cos(20^\circ)
  3. 3.0 N: This force is along the negative yy-axis and does not have an xx-component.

Adding these up gives the net force in the xx-direction: Fx=1.0+5.0cos(20)F_x = 1.0 + 5.0 \cos(20^\circ) Once we have the total force, we can calculate the acceleration using Fx=maxF_x = ma_x. However, to get the acceleration axa_x, we also need the mass mm of the object, which is not provided in the diagram. If you have the mass, we can continue from there, but if it's not provided, we'll assume it's a known variable.

Let me know if you have the mass or if you'd like to clarify further!


Here are some questions that may help extend this:

  1. What is the object's mass?
  2. Do you need the yy-component of the acceleration as well?
  3. Should we calculate the net acceleration (magnitude and direction)?
  4. Do you need a breakdown of the trigonometric components?
  5. Would you like to know how to resolve forces in both axes?

Tip: Always resolve forces along each axis separately and then apply Newton's laws.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Newton's Second Law
Trigonometry
Force Resolution

Formulas

F = ma
F_x = F \cos(\theta)

Theorems

Newton's Second Law of Motion

Suitable Grade Level

Grades 11-12