1. A Cessna 172R has a Lycoming 10-360 engine that creates 180 horsepower at 2,700 rpm. How many pound-feet of torque is the engine producing?

To calculate the torque produced by an engine, we can use the formula:

\[
\text{Torque (lb-ft)} = \frac{\text{Horsepower} \times 5252}{\text{RPM}}
\]

where:

- Horsepower is the power output (180 HP in this case).
- 5252 is a constant that comes from converting the units appropriately (it relates horsepower, RPM, and torque).
- RPM is the revolutions per minute (2700 RPM in this case).

Let's apply this formula:

\[
\text{Torque} = \frac{180 \times 5252}{2700}
\]

Calculating:

\[
\text{Torque} = \frac{945360}{2700} \approx 350 \text{ lb-ft}
\]

Thus, the engine is producing approximately **350 pound-feet** of torque.

Would you like more details or have any questions? Here are some related questions for further exploration:

1. How is the constant 5252 derived in the torque formula?
2. How does torque affect the performance of an aircraft engine?
3. What is the significance of RPM in determining the engine's power output?
4. How would changing the RPM impact the torque and horsepower?
5. What is the difference between torque and

A Cessna 172R has a Lycoming 10-360 engine that creates 180 horsepower at 2,700 rpm. How many pound-feet of torque is the engine producing?

Discover how to calculate the torque produced by a Cessna 172R engine using the horsepower (180 HP) and RPM (2700). This problem involves applying the torque formula and understanding the relationship between horsepower, RPM, and torque. Suitable for students in Grades 10-12.

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