You have measured an acoustic power of 9.0 x 10^(-5) W using a device with a sensor that has a surface area of 5.0 x 10^(-5) m^2. What is the sound intensity level of this sound?
*
4 points
0.18 W/m^2
1.8 W/m^2
18 W/m^2

The **sound intensity level** (also known as sound intensity) can be calculated using the formula for **intensity**:

\[
I = \frac{P}{A}
\]

where:
- \(I\) is the intensity in watts per square meter (W/m²),
- \(P\) is the acoustic power in watts (W),
- \(A\) is the surface area in square meters (m²).

### Given:
- \(P = 9.0 \times 10^{-5}\) W,
- \(A = 5.0 \times 10^{-5}\) m².

### Plugging in the values:

\[
I = \frac{9.0 \times 10^{-5} \, \text{W}}{5.0 \times 10^{-5} \, \text{m}^2} = 1.8 \, \text{W/m}^2
\]

Thus, the **sound intensity level** is **1.8 W/m²**.

### Correct answer:  
**1.8 W/m²**

Let me know if you'd like more details, or have any further questions!  
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Here are 5 related questions for you to explore:

1. What is the relationship between sound intensity and sound pressure?
2. How does the intensity level of sound affect human hearing?
3. How do you calculate sound intensity in decibels (dB)?
4. What factors could affect the measured intensity of sound in a specific area?
5. How does the inverse square law relate to sound intensity in a free field?

**Tip:**  
The **inverse square law** tells us that the intensity of sound decreases with the square of the distance from the source.

You have measured an acoustic power of 9.0 x 10^(-5) W using a device with a sensor that has a surface area of 5.0 x 10^(-5) m^2. What is the sound intensity level of this sound?

Learn how to calculate the sound intensity level from acoustic power and sensor surface area. In this problem, we calculate the sound intensity level using a given power of 9.0 x 10^-5 W and a sensor area of 5.0 x 10^-5 m². The result is 1.8 W/m², suitable for high school students.

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