The sound intensity level (also known as sound intensity) can be calculated using the formula for intensity:

$I = \frac{P}{A}$

where:

• $I$ is the intensity in watts per square meter (W/m²),
• $P$ is the acoustic power in watts (W),
• $A$ is the surface area in square meters (m²).

Given:

• $P = 9.0 \times 10^{-5}$ W,
• $A = 5.0 \times 10^{-5}$ m².

Plugging in the values:

$I = \frac{9.0 \times 10^{-5} \, \text{W}}{5.0 \times 10^{-5} \, \text{m}^2} = 1.8 \, \text{W/m}^2$

Thus, the sound intensity level is 1.8 W/m².

Correct answer:

1.8 W/m²

Let me know if you'd like more details, or have any further questions!

Here are 5 related questions for you to explore:

1. What is the relationship between sound intensity and sound pressure?
2. How does the intensity level of sound affect human hearing?
3. How do you calculate sound intensity in decibels (dB)?
4. What factors could affect the measured intensity of sound in a specific area?
5. How does the inverse square law relate to sound intensity in a free field?

Tip:
The inverse square law tells us that the intensity of sound decreases with the square of the distance from the source.