The given triangle has the following details:

• Hypotenuse ($c$) = 17
• One angle = 10°
• $a$ is the side opposite the 10° angle.
• $b$ is the adjacent side (opposite angle $B$).

We can use trigonometric functions to solve for $a$ and $b$.

1. Finding $a$ (opposite side):

Using the sine function: $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \quad \Rightarrow \quad a = \text{hypotenuse} \times \sin(10^\circ)$

2. Finding $b$ (adjacent side):

Using the cosine function: $\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \quad \Rightarrow \quad b = \text{hypotenuse} \times \cos(10^\circ)$

I'll calculate these values now.The values of the sides are:

• $a \approx 2.9520$
• $b \approx 16.7417$

Would you like more details or have any questions?

Here are some related questions for further exploration:

1. How would the values of $a$ and $b$ change if the angle increased to 20°?
2. How does changing the length of the hypotenuse affect the values of $a$ and $b$?
3. Can you use tangent to calculate either side in this problem?
4. What is the relationship between sine and cosine for complementary angles in this context?
5. How would you solve this problem using the Pythagorean theorem after finding one side?

Tip: When solving right triangles, always check if you can use the sine, cosine, or tangent based on the information provided.