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The problem asks how many pages Colton would read in one hour (60 minutes) given that he reads 19 1/3 pages in 20 minutes at a constant rate. Let's solve this step by step:

### Step 1: Convert the mixed number
Colton reads **19 1/3 pages** in 20 minutes. Convert this to an improper fraction:
\[
19 \frac{1}{3} = \frac{58}{3} \text{ pages}
\]
This is the number of pages he reads in 20 minutes.

### Step 2: Determine pages per minute
Since Colton reads \(\frac{58}{3}\) pages in 20 minutes, the number of pages he reads per minute is:
\[
\frac{58}{3} \div 20 = \frac{58}{3} \times \frac{1}{20} = \frac{58}{60} = \frac{29}{30} \text{ pages per minute}
\]

### Step 3: Calculate the number of pages read in 60 minutes
To find how many pages he reads in 60 minutes, multiply the pages per minute by 60:
\[
\frac{29}{30} \times 60 = \frac{29 \times 60}{30} = \frac{1740}{30} = 58 \text{ pages}
\]

### Final Answer: 
Colton will read **58 pages** in one hour (60 minutes).

Would you like further details or have any questions?

Here are five related questions:
1. How would the result change if Colton read faster or slower?
2. What if Colton read 25 pages in 20 minutes instead? How many in one hour?
3. How do you convert between mixed numbers and improper fractions?
4. How can you generalize this problem for any number of pages and minutes?
5. What is the importance of unit rates in solving real-life problems?

**Tip:** Always convert mixed numbers to improper fractions before performing calculations, as it simplifies the arithmetic.

Colton read 19 1/3 pages in 20 minutes. If he reads at a constant rate, how many pages did he read in one hour?

Learn how to solve the problem of determining how many pages Colton reads in one hour at a constant rate. This exercise covers converting mixed numbers to improper fractions, calculating rates, and unit conversions. Suitable for middle school students (Grades 6-8).

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