Math Problem Statement

Find the mean, median, and mode for each data set. a) 12, 16, 11, 15, 21, 13, 17, 17, 15, 24, 20, 16 b) 15.2, 15.8, 15.9, 15.3, 14.8, 13.7, 15.9, 14.5, 14.6, 15.8 c) 0.034, 0.045, 0.043, 0.037, 0.036, 0.041, 0.040 d) 15, 17, 17, 17, 18, 19, 25, 37, 37, 42, 50, 61, 70, 85

Solution

Here are the calculated mean, median, and mode for each data set:

a) 12,16,11,15,21,13,17,17,15,24,20,1612, 16, 11, 15, 21, 13, 17, 17, 15, 24, 20, 16

  • Mean: 16.42
  • Median: 16.0
  • Mode: 15

b) 15.2,15.8,15.9,15.3,14.8,13.7,15.9,14.5,14.6,15.815.2, 15.8, 15.9, 15.3, 14.8, 13.7, 15.9, 14.5, 14.6, 15.8

  • Mean: 15.15
  • Median: 15.25
  • Mode: 15.8

c) 0.034,0.045,0.043,0.037,0.036,0.041,0.0400.034, 0.045, 0.043, 0.037, 0.036, 0.041, 0.040

  • Mean: 0.0394
  • Median: 0.04
  • Mode: 0.034

d) 15,17,17,17,18,19,25,37,37,42,50,61,70,8515, 17, 17, 17, 18, 19, 25, 37, 37, 42, 50, 61, 70, 85

  • Mean: 36.43
  • Median: 31.0
  • Mode: 17

Would you like further clarification or details on these calculations?

Here are some related questions:

  1. What is the effect of outliers on the mean and median of a data set?
  2. How can we determine the range of a data set, and what does it indicate?
  3. What is the significance of the mode in different types of data sets?
  4. How do we handle multiple modes in a data set?
  5. Can we use other measures of central tendency for skewed distributions?

Tip: The mean is sensitive to outliers, while the median is more resistant to extreme values.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Measures of Central Tendency

Formulas

Mean = (sum of all data points) / (number of data points)
Median = middle value in a sorted data set
Mode = most frequent value in the data set

Theorems

-

Suitable Grade Level

Grades 6-8