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The image contains a problem related to vector magnitudes and their angle.

The problem appears to be:  
- Two vectors \( \vec{A} \) and \( \vec{B} \) are given, where \( |\vec{A}| = 4 \, \text{m} \) and \( |\vec{B}| = 5 \, \text{m} \).  
- The angle between these two vectors is \( 60^\circ \).
- The task is to calculate \( |\vec{A} + \vec{B}| \), the magnitude of the resultant vector.

The formula for the magnitude of the resultant vector \( \vec{A} + \vec{B} \) is:
\[
|\vec{A} + \vec{B}| = \sqrt{|\vec{A}|^2 + |\vec{B}|^2 + 2|\vec{A}||\vec{B}|\cos(\theta)}
\]
where:
- \( |\vec{A}| = 4 \, \text{m} \),
- \( |\vec{B}| = 5 \, \text{m} \),
- \( \theta = 60^\circ \).

Let me calculate the magnitude.

Two vectors \( \vec{A} \) and \( \vec{B} \) are given, where \( |\vec{A}| = 4 \, \text{m} \) and \( |\vec{B}| = 5 \, \text{m} \). The angle between these two vectors is \( 60^\circ \). The task is to calculate \( |\vec{A} + \vec{B}| \), the magnitude of the resultant vector.

Explore how to calculate the magnitude of a resultant vector given vectors A and B with magnitudes of 4 m and 5 m, respectively, and an angle of 60 degrees between them. This problem covers key vector concepts, including vector magnitude, addition, and the application of the cosine rule for vectors. Suitable for students in Grades 10-12.

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