a pole leans at an angle of 6degrees to the vertical. when the elevation of sun is 50degrees, the pole casts a shadow of 48ft long on level ground. how long is the pole

To solve this problem, we can use trigonometry. Let’s break down the solution:

1. **Identify the components of the pole and shadow**:
   - Let \( L \) be the length of the pole.
   - The pole leans 6 degrees from the vertical.
   - The sun's elevation angle is 50 degrees.
   - The shadow length is 48 feet.

2. **Set up the triangle**:
   - We can visualize a right triangle where the shadow forms the horizontal base, and the pole forms the hypotenuse.
   - The angle between the pole and the shadow is \( 50^\circ + 6^\circ = 56^\circ \).

3. **Apply the Law of Cosines**:
   We can use the Law of Cosines to find the length of the pole \( L \):
   \[
   L^2 = 48^2 + h^2

A pole leans at an angle of 6 degrees to the vertical. When the elevation of the sun is 50 degrees, the pole casts a shadow of 48ft long on level ground. How long is the pole?

Learn how to calculate the length of a pole leaning at 6 degrees with a shadow of 48 feet. The problem involves the use of trigonometric concepts like the Law of Cosines and right triangles. Suitable for high school students in Grades 10-12.

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