To solve the given problem, we will: 1. Convert the semi-major axis (\(a\)) and period (\(P\)) for each moon into the appropriate units: - \(a\) to Astronomical Units (AU), - \(P\) to years. 2. Use Kepler's Third Law, modified by Newton: \[ M_J = \frac{a^3}{P^2} \] where \(M_J\) is the mass of Jupiter in Solar Mass units (\(M_\odot\)). 3. Calculate the values of \(a^3\), \(P^2\), and \(M_J\) for each moon. 4. Compute the mean value of \(M_J\), convert it into kilograms using \(M_\odot = 1.99 \times 10^{30} \, \text{kg}\), and compare it to the accepted value of \(M_J = 1.898 \times 10^{27} \, \text{kg}\). Please share the values from Table 1 so we can proceed with the calculations. Alternatively, let me know if you'd like