$2500 at 3.24% compounded quarterly for 9 years.

To calculate the future value of $2,500 invested at 3.24% compounded quarterly for 9 years, we can use the compound interest formula:

\[
A = P \left(1 + \frac{r}{n}\right)^{nt}
\]

Where:
- $A$ is the future value of the investment/loan, including interest.
- $P$ is the principal amount ($2,500).
- $r$ is the annual interest rate (3.24% or 0.0324 as a decimal).
- $n$ is the number of times the interest is compounded per year (quarterly means $n = 4$).
- $t$ is the time the money is invested for, in years (9 years).

### Plugging in the values:

\[
A = 2500 \left(1 + \frac{0.0324}{4}\right)^{4 \times 9}
\]

\[
A = 2500 \left(1 + 0.0081\right)^{36}
\]

\[
A = 2500 \left(1.0081\right)^{36}
\]

Now, calculate:

\[
A = 2500 \times 1.3246 \quad (\text{rounded to four decimal places})
\]

\[
A \approx 3311.50
\]

So, the future value of the investment is approximately **$3,311.50**.

Would you like more details on how this was calculated or have any other questions?

Here are 5 related questions you might find useful:
1. What would the future value be if the interest was compounded monthly instead of quarterly?
2. How would the future value change with a different interest rate?
3. What is the difference between simple interest and compound interest for the same time period?
4. How can you calculate the total interest earned over the 9 years?
5. How would the investment grow over 12 years instead of 9?

**Tip:** Compounding frequency significantly impacts the growth of your investment—more frequent compounding results in higher returns over time.

Learn how to calculate the future value of $2500 invested at an interest rate of 3.24% compounded quarterly for 9 years. This problem involves compound interest and exponential growth concepts, suitable for students in Grades 10-12.

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